Let t = the number of days the mouse travels
Let D = the distance that the mouse traveled
The mouse travels at a rate of 1.5 miles per day, so R = 1.5 mi/day
The equation is:
Distance (D) = Rate (R) x Time (t)
SO:
Distance (D) = 1.5 mi./day X Time (t)
Answer:
a) All of them are out of charge = 9.31x10⁻¹⁰
b) 20% of them are out of charge = 5.529x10⁻⁴
Step-by-step explanation:
This problem can be modeled as a binomial distribution since
There are n repeated trials and all of them are independent of each other.
There are only two possibilities: battery is out of charge and battery is not out of charge.
The probability of success does not change with trial to trial.
Since it is given that it is equally likely for the battery to be out of charge or not out of charge so probability of success is 50% or 0.50
P = 0.50
1 - P = 0.50
a) All of them are out of charge?
Probability = nCx * P^x * (1 - P)^n-x
Probability = ₃₀C₃₀(0.50)³⁰(0.50)⁰
Probability = 9.31x10⁻¹⁰
b) 20% of them are out of charge?
0.20*30 = 6 batteries are out of charge
Probability =₃₀C₆(0.50)²⁴(0.50)⁶
Probability = 5.529x10⁻⁴
Height = 12 cm
Base/width —> half of height —> 12/2 = 6 cm
Area = length x width
Area —> 12x6 = 72
The sticker covers 72 cm of the notebook.
Answer:
2(2/5x+2)= 2*2/5x + 2*2= 4/5x+4
