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Alja [10]
3 years ago
15

Please help! Sarah’s dogs:

Mathematics
1 answer:
olchik [2.2K]3 years ago
6 0

Answer:

For Sarah's dogs, we have:

Morning:

39, 21, 12, 27, 23, 19, 19, 31, 36, 25

if the ranges are:

A) 10 pounds to 19 pounds: here we have the dog of 12, and two dogs of 19.

B) 20 to 29: one of 21 pounds, one of 27, one of 23 and one of 25, so here we have 4 dogs.

C) 30 to 39. here we have the left 3 dogs.

then the table is:

\left[\begin{array}{ccc}range&dogs\\10to19&3\\20to29&4\\30to39&3\end{array}\right]

For the afternoon, the weights of the dogs are:

15, 51, 8, 16, 43, 34, 27, 11, 8, 39

So the ranges:

0 to 9: here we have two dogs of 8.

10 to 19: 3 dogs, 15, 16 and 11.

20 to 29: 1 dog of 27

30 to 39: 2 dogs of 34 and 39

40 to 49: one dog of 43

50 to 59: one dog of 51.

the table is:

\left[\begin{array}{ccc}range&dogs\\0to9&2\\10to19&3\\20to29&1\\30to39&2\\40to49&1\\50to59&1\end{array}\right]

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Approximately how many times greater is 1.2×103 than 4×10−1 ?
Galina-37 [17]
3000 Quick answer
Let your calculator do the work. Be careful how you enter this in. (Are you supposed to estimate it? We'll get around to that.) Write it like this.

1.2 * 10^3 divided by 4 * 10^-1 Your calculator will do this nicely. The trick is the - 1. Put it in the calculator like this.
1.2 
*
10
^
3
=
÷
4
*
10
^
(-1) 
= The calculator should read 3000
That's one way to do it. Another way is just to do it all by hand. The numbers are easy enough
1.2 * 10^3 means shift the decimal 3 places right. 1 200 which is 1200
4 * 10^-1 can be handled 2 ways 10 to the minus 1 in the denominator becomes 10^1 in the numerator. Notice the sign change on the 10 when you shift if :it becomes plus! That's why you did it.

1200 * 10^1 
12000

Now you are still left with 4 in the denominator.
12000/4 = 3000. 

The first method always works. The second one gives you a better understanding of how powers work. There are other ways of doing this, but these are the two best, I think.
4 0
3 years ago
Part A: Factor 2x2c2 + 3xc2 − 35c2. Show your work. (4 points) Part B: Factor x2 + 20x + 100. Show your work. (3 points) Part C:
Paraphin [41]
A.\\2x^2c^2+3xc^2-35c^2=c^2(2x^2+3x-35)=c^2(2x^2+10x-7x-35)\\\\=c^2[2x(x+5)-7(x+5)]=c^2(x+5)(2x-7)


B.\\x^2+20x+100=x^2+10x+10x+100=x(x+10)+10(x+10)\\\\=(x+10)(x+10)=(x+10)^2


C.\\x^2-144=x^2-12^2=(x-12)(x+12)\\\\used:\ a^2-b^2=(a-b)(a+b)
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fenix001 [56]
2.............................................
5 0
4 years ago
Please help and explain!!!!
KengaRu [80]

Answer:

The expression is: 100 -a - 2b

Step-by-step explanation:

One piece of length a and two pieces of length b, i.e., (2 times b) are a total length of (a + 2b). We are asked to express the remaining part of the wire, originally 100 cm long, so that must be 100 minus the total pieces cut out:

100 - ( a + 2b ) = 100 -a -2b

3 0
3 years ago
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Svetllana [295]

Answer:

[1. 10.5] [2. 8.4] [3. 7.7]

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