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Alja [10]
3 years ago
15

Please help! Sarah’s dogs:

Mathematics
1 answer:
olchik [2.2K]3 years ago
6 0

Answer:

For Sarah's dogs, we have:

Morning:

39, 21, 12, 27, 23, 19, 19, 31, 36, 25

if the ranges are:

A) 10 pounds to 19 pounds: here we have the dog of 12, and two dogs of 19.

B) 20 to 29: one of 21 pounds, one of 27, one of 23 and one of 25, so here we have 4 dogs.

C) 30 to 39. here we have the left 3 dogs.

then the table is:

\left[\begin{array}{ccc}range&dogs\\10to19&3\\20to29&4\\30to39&3\end{array}\right]

For the afternoon, the weights of the dogs are:

15, 51, 8, 16, 43, 34, 27, 11, 8, 39

So the ranges:

0 to 9: here we have two dogs of 8.

10 to 19: 3 dogs, 15, 16 and 11.

20 to 29: 1 dog of 27

30 to 39: 2 dogs of 34 and 39

40 to 49: one dog of 43

50 to 59: one dog of 51.

the table is:

\left[\begin{array}{ccc}range&dogs\\0to9&2\\10to19&3\\20to29&1\\30to39&2\\40to49&1\\50to59&1\end{array}\right]

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Answer:

To see how these fractions are equal, I divided the numerators by the denominators. For instance, you could have 4 over 5 (4/5) and divide 4 by 5 (4/5) to get 0.8. Now you'll do the same thing for the fractions given

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