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3 years ago

The perimeter of a rectangle is 68cm. The length is four cm. more than the width. Find the dimensions of the rectangle

Mathematics

1 answer:

Julli [10]3 years ago

8 0

Width is 15cm length 19cm

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I would really appreciate it if y'all gave me an answer pls

Makovka662 [10]

Answer:

The answer of this question is 78°.

Step-by-step explanation:

Let angle X be denoted by y then angle Z=y (because isosceles angles of a traingle is equal)

Now,

y+y+24°=189°

2y+24°=180°

2y=180°-24°

y=156/2

y=78°

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3 years ago

Two numbers multiply to be -100 and add to 0

ipn [44]

Well, +10 and -10 can do that job.

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3 years ago

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kirill115 [55]

Answer:

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3 years ago

The ratio of AB to BC is 1/3<br> True or False

marshall27 [118]

AB/BC = 3/9 = 1/3
answer
True

8 0

3 years ago

Read 2 more answers

WORTH 20 POINTS HELP

vfiekz [6]

Below represents the proof that the quadrilateral QRST is a parallelogram

<h3>How to prove that QRST is a parallelogram?</h3>

The coordinates are given as:

Q = (-1,-1)

R = (2,9)

S = (-4,5)

T = (-7,-5)

Calculate the length of each side using:

$d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}$

So, we have:

$QR = \sqrt{(-1 - 2)^2 + (-1 -9)^2} = \sqrt{109}$

$RS = \sqrt{(-4 - 2)^2 + (5 - 9)^2} = \sqrt{52}$

$ST = \sqrt{(-7 + 4)^2 + (-5 - 5)^2} = \sqrt{109}$

$TQ = \sqrt{(-7 + 1)^2 + (-5 + 1)^2} = \sqrt{52}$

The above computations show that opposite sides are equal.

Next, we determine the slope of each side using:

$m = \frac{y_2 -y_1}{x_2 -x_1}$

So, we have:

$QR = \frac{9 + 1}{2 + 3} = \frac{10}3$

$RS = \frac{5-9}{-4 - 2} = \frac{2}3$

$ST = \frac{5+5}{-4 + 7} = \frac{10}3$

$TQ = \frac{-5+1}{-7 + 1} = \frac{2}3$

The above computations show that opposite sides are parallel, because they have equal slope

Hence, the quadrilateral QRST is a parallelogram