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tigry1 [53]
3 years ago
5

lynn, jude and anne were given the function f(x)=-2x^2+32, and they were asked to find f(3). lynns answer was 14, judes answer w

as 4, and annes answer was +-4. who is correct?
Mathematics
1 answer:
AfilCa [17]3 years ago
6 0
The only thing we need to here to find who is correct is evaluate the function f(x)=-2 x^{2} +32 at x=3. To do that we are going to replace x with 3 in the function:
f(x)=-2 x^{2} +32
f(3)=-2 (3)^{2} +32
f(3)=-2 (9) +32
f(3)=-18+32
f(3)=14

We can conclude that Lynn is correct. f(3) is indeed 14.
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Evaluate the definite integral. <br> 1 x4(1 + 2x5)5 dx.
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Answer:

Step-by-step explanation:

Given the definite integral \int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx, we to evaluate it. Using integration by substitution method.

Let u = 1-2x⁵ ...1

du/dx = -10x⁴

dx = du/-10x⁴.... 2

Substitute equation 1 and 2 into the integral function and evaluate the resulting integral as shown;

= \int\limits {\dfrac{x^4}{u^5} } \, \dfrac{du}{-10x^4}

= \dfrac{-1}{10} \int\limits {\dfrac{du}{u^5} }  \\\\= \dfrac{-1}{10} \int\limits {{u^{-5}du }  \\= \dfrac{-1}{10} [{\frac{u^{-5+1}}{-5+1}]  \\\\= \dfrac{-1}{10} ({\frac{u^{-4}}{-4})\\\\

= \dfrac{u^{-4}}{40} \\\\\\= \dfrac{1}{40u^4} +C

substitute u = 1-2x⁵ into the result

= \dfrac{1}{40(1-2x^5)^4} +C

Hence\int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx = \dfrac{1}{40(1-2x^5)^4} +C

5 0
2 years ago
I need with the volume!!!
murzikaleks [220]

Answer:

Tim read 81 pages.

Step-by-step explanation:

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Wednesday: 9 x 3 = 27

Thursday: 27 x 3 = 81

I hope this helps you! :D

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