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Ganezh [65]
3 years ago
14

Which shows all the names that apply to the figure?

Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
6 0
D, Parallelogram

This is because there are two sets of parallel sides but not two sets of sides with equal length.
Sloan [31]3 years ago
4 0
Hey there!

<span>Which shows all the names that apply to the figure?

Answer: </span>
<span>
D.


parallelogram

Hope this helps! (:
</span>
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Find percentage notation for 300/800
astra-53 [7]
37.5 % of 800 is 300 because of division
7 0
3 years ago
Timothy put $300 in a bank that pays 7% interest rate, if he leaves his interest from the first year in the bank, how much money
andriy [413]

Answer: he would have $343.47 after 2 years.

Step-by-step explanation:

if he leaves his interest from the first year in the bank, we would assume that his interest was compounded. We would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = $300

r = 7% = 7/100 = 0.07

n = 1 because it was compounded once in a year.

t = 2 years

Therefore,.

A = 300(1 + 0.07/1)^1 × 2

A = 300(1.07)^2

A = $343.47

7 0
3 years ago
Enlarge shape a by 1/3 with the centre enlargement (3,-3) <br> (-9,9) (-9,6) (-3,6)
NemiM [27]

Answer:

0033

Step-by-step explanation:

.033 of a whole number so its .033

5 0
3 years ago
Here you go Anne :0)
gladu [14]

Answer:

Hey dude............... option 1...

5 0
3 years ago
our buses carrying 140 high school students arrive to Montreal. The buses carry, respectively, 31, 43, 27, and 39 students. One
Vinvika [58]

Answer:

V(X)= 39.10

V(Y)= 40

Step-by-step explanation:

Given that

Total number of student = 140

Bus A - 31

Bus B- 43

Bus C- 27

Bus D- 39

The probability that a student was on the bus is proportional to the number of student. Eg 31/140 in bus A, 43/140 on bus B, ...

E(X) = (31*31/140) + (43*43/140)  + (27*27/140) + (39*39/140)

=  35.5

Var(X) =(31-35.5)^2 \times \dfrac{31}{140}+(43-35.5)^2 \times \dfrac{43}{140}+(39-35.5)^2 \times \dfrac{39}{140}+(27-35.5)^2 \times \dfrac{27}{140}

V(X)= 39.10

The bus driver have  1/4 probability on being on any of the buses.

E(Y) = 140/4 = 35

Var(Y)=\dfrac{(35-31)^2+(35-43)^2+(35-27)^2+(35-39)^2}{4}

V(Y)= 40

7 0
3 years ago
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