Answer:
Step-by-step explanation:
The standard form of a linear equation, a line, is y = mx + b, where m is the slope. The rule is the higher this value of m, the steeper the graph is. If we have the original equation y = 3x + 1, its slope m is 3; in the "new" equation, y = x + 1, its slope is 1. So the "new" equation would be less steep because the slope is a lower value than the original.
Answer:
1. 4 hours and 10 minutes
2. 8:40 to 12:00
4. 6 hours and 50 minutes
5. 2:25 pm
6. 9:15 am to 12:35pm
7. 3:00pm
(second) 7. 2 hours and 45 minutes
Step-by-step explanation:
1. 2+4 = 6 so then after add 10 to the 45
4 hours and 10 mins
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2. 8+3= 11 so its 11:40 right now, add the other 20 minutes, you end up with 12:00.
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4.It's better off to start with 12 so add 3 hours and 30 minutes to get to 12:00pm. Now to 3:20pm would obviously be 3 hours and 20 minutes.
3 hours + 3 hours = 6 hours. 30 minutes + 20 mins = 50 mins. 6 hours and 50 minutes.
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5. 10:15 + 4 hours would be 2:15 now add the 10 and that would be 2:25pm.
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6. 9:15 a.m to 12:35pm would be right. The elapsed time is 5 hours and 20 minutes. 10:30 P.M to 1:15 A.M would be close but it's 5 minutes lesser. 11:10 pm to 2:15 am would be 3 hours and 5 minutes. 6:45pm to 10:00pm would be 3 hours and 15 minutes.
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7. Making it simpler, add 15 minutes so that makes it 12:00pm. Then just add the 3 hours. 3:00P.M.
3:00 pm is your answer.
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(second) 7. 10:30 pm to 1:15am. Also making it simpler, add 1 hour and 30 minutes. Now just add 1 hour and 15 minutes. Add both times,
1 hour and 30 minutes + 1 hour and 15 minutes = 2 hours and 45 minutes.
The answer is c b/c you multiply
Answer:
Mean
Step-by-step explanation:
Adding up and dividing to find the mean.
We simply add up all of the individual grades, get the total, and then divide by the number of students in the class.
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Answer:
C
Step-by-step explanation:
One pound (lb) is equal to 16 (oz). So, if you are trying to find how many ounces are in one pound, you have to divide the number of pounds by the 16, the amount of ounces in one pound.