Answer:
The required sample size for the new study is 801.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

25% of all adults had used the Internet for such a purpose
This means that 
95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
What is the required sample size for the new study?
This is n for which M = 0.03. So






Rounding up:
The required sample size for the new study is 801.
Answer:
So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.
Step-by-step explanation:
The height h of the ball is modeled by the following equation

The problem want you to find the times the ball will be 48 feet above the ground.
It is going to be when:





We can simplify by 16t. So

It means that
16t = 0
t = 0
or
t - 2 = 0
t = 2
So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.
Answer:
4 days
Step-by-step explanation:
216/3 = 72
72/18 = 4
To find c, you must isolate it.
To do this, you must divide both sides by 5/7, since that is being multiplied by c and you must do the inverse to it to cancel it out in order to leave c by itself.
5/7c ÷ 5/7 = c
13/14 ÷ 5/7
To divide fractions, follow these steps:
Step 1- Turn the second fraction, 5/7 in this case, into its reciprocal. This means swapping the places of the numerator and denominator.
5/7 reciprocal = 7/5
Step 2- multiply the original first fraction and reciprocal second fraction.
13/14 • 7/5
13 • 7 = 91
14 • 5 = 70
13/14 ÷ 5/7 = 91/70
Step 3- Simplify if possible.
91/70
Since 70 can go into 90, you can turn this into a mixed number.
1 and 21/70
Now simplify 21/70.
Both can be divided by 7.
21 ÷ 7 = 3
70 ÷ 7 = 10
So simplified, 91/70 equals 1 and 3/10.
As a decimal, this is 1.3.
So the answer is c = 1.3, or 1 and 3/10.
Hope this helps :)
Answer:
How is that possible
Step-by-step explanation: