Answer:
I believe it is Option 1
Step-by-step explanation:
Since the fourth root of 81 will be 3 and of 16 will be 2.
Answer: (15.47, 24.53)
Step-by-step explanation:
We know that the confidence interval for population mean is given by :_
![\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=%5Coverline%7Bx%7D%5Cpm%20z%5E%2A%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
, where n= sample size.
= standard deviation.
= sample mean.
z*= Critical value.
Given : n= 450
![\overline{x}=20](https://tex.z-dn.net/?f=%5Coverline%7Bx%7D%3D20)
![\sigma=49](https://tex.z-dn.net/?f=%5Csigma%3D49)
Critical value for 95% confidence = z*=1.96 [From z-value table]
Then, the 95% confidence interval will be :-
![20\pm (1.96)\dfrac{49}{\sqrt{450}}](https://tex.z-dn.net/?f=20%5Cpm%20%281.96%29%5Cdfrac%7B49%7D%7B%5Csqrt%7B450%7D%7D)
![\approx 20\pm (1.96)(2.31)](https://tex.z-dn.net/?f=%5Capprox%2020%5Cpm%20%281.96%29%282.31%29)
![\approx 20\pm 4.53](https://tex.z-dn.net/?f=%5Capprox%2020%5Cpm%204.53)
![=(20-4.53,\ 20+4.53)=(15.47,\ 24.53)](https://tex.z-dn.net/?f=%3D%2820-4.53%2C%5C%2020%2B4.53%29%3D%2815.47%2C%5C%2024.53%29)
Hence, the 95% confidence interval for the mean change in score μ μ in the population of all high school seniors. : (15.47, 24.53)
Answer:
-40
Step-by-step explanation:
h(x) = -7(6) +2
-42+2 = -40
he will pay $31 in interest after 6 months so after 6 months he will pay $531
Answer:
x= -3
y= -4
Step-by-step explanation:
If 11/17 and x goes together then this is what I got. Oh plug them in in case its wrong. Good Luck