See attached picture for steps
I think is that one that say <-5,-3> yeah because 3×5=15 you have to choose what other number × 3 that equal to that following answer.
Use this rule: <em>(x^a)^b = x^ab</em>
3(x + 2)^3/5 + 2 = 27
Subtract 3 from both sides
3(x + 2)^3/5 = 27 - 3
Simplify 27 - 3 to 24
3(x + 2)^3/5 = 24
Divide both sides by 3
(x + 2)^3/5 = 24/3
Simplify 24/3 to 8
(x + 2)^3/5 = 8
Take the cube root of both sides
x + 2 = 3/5√8
Invert and multiply
x + 2 = 8^5/3
Calculate
x + 2 = 2^5
Simplify 2^5 to 32
x + 2 = 32
Subtract 2 from both sides
x = 32 - 2
Simplify 32 - 3 to 30
<u>x = 30</u>
This isn't really a geometry problem. It's just an addition of fractions.
You know that 'perimeter' means 'the distance all the way around'.
And you know the length of all the sides of the parallelogram.
All you need to do is add them up !
(13/12) + (3/13) + (13/12) + (3/13) = the perimeter
Notice that two of the sides are equal, and the other two sides are also equal.
So you can make the job a little easier if you add up the twelfths first
(13/12) + (13/12) = 26/12
and then add up the thirteenths ...
(3/13) + (3/13) = 6/13 .
Now, the perimeter looks a little bit less complicated.
It's just
(26/12) + (6/13) = the perimeter.
This is the tough part. Before you can add fractions, they need to have
a common denominator.
The smallest common denominator for 12ths and 13ths is <em>156 </em>!
Change each fraction to (<em>something over 156</em>), and add um up.
I'll leave that part to you.
The correct answer here would be the third choice or NK
hope this helps
