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oksano4ka [1.4K]
3 years ago
6

A game at the fair involves a wheel with seven sectors. Two of the sectors are red, two of the sectors are purple, two of the se

ctors are yellow, and one sector is blue. Landing on the blue sector will give 3 points, landing on a yellow sector will give 1 point, landing on a purple sector will give 0 points, and landing on a red sector will give –1 point.
If you take one spin, what is your expected value?

What changes could you make to values assigned to outcomes to make the game fair? Prove that the game would be fair using expected values.
Mathematics
1 answer:
Zolol [24]3 years ago
7 0

Answer:

Expected value: 3/7

Change landing on purple to -1.5

Step-by-step explanation:

Expected value

=3(1/7) + 1(2/7) + 0(2/7) - 1(2/7) = 3/7

Fair game: Expected value = 0

Change the value of 0 to -1.5

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Now multiplying each term by -1,

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Factor greatest common factors out,

\sin(x)(2 \sin(x) - 1) = 0

Applying Zero property rule,

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• Solve the trignometric equation to find a particular solution,

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=  > x = 2nπ \: or \: x = π + 2nπ

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<h3><u>{</u> <u>For</u><u> </u><u>2</u><u> </u><u>sin</u><u>(</u><u>x</u><u>)</u><u> </u><u>-</u><u> </u><u>1</u><u> </u><u>=</u><u> </u><u>0</u> ,</h3>

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}

☆ Now finding the union of both sets

x = nπ \: or \: x =  \frac{π}{6} + 2nπ \: or \: x =  \frac{5π}{6} + 2nπ,n∈Z

Hence, the answer is x = nπ \: or \: x =  \frac{π}{6} + 2nπ \: or \: x =  \frac{5π}{6} + 2nπ,n∈Z

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