Question

Write the equation of a line that is perpendicular to y=3/2x+2 that goes through (6,-3)

Answer 1

Answer:

$y + 3 = -\frac{2}{3}(x-6)$

Step-by-step explanation:

Perpendicular lines are lines which intersect at 90 degrees which have negative reciprocal slopes. The slope of the line y = 3/2x + 2 is 3/2. The slope of the line perpendicular to it will be -2/3. Substitute m = -2/3 and (6,-3) into the point slope form of a line.

$y - y_1 = m(x-x_1)\\y - -3 = -\frac{2}{3}(x-6)\\y + 3 = -\frac{2}{3}(x-6)$