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gogolik [260]
3 years ago
7

Write the equation of a line that is perpendicular to y=3/2x+2 that goes through (6,-3)

Mathematics
1 answer:
scoray [572]3 years ago
4 0

Answer:

y + 3 = -\frac{2}{3}(x-6)

Step-by-step explanation:

Perpendicular lines are lines which intersect at 90 degrees which have negative reciprocal slopes. The slope of the line y = 3/2x + 2 is 3/2. The slope of the line perpendicular to it will be -2/3. Substitute m = -2/3 and (6,-3) into the point slope form of a line.

y - y_1 = m(x-x_1)\\y - -3 = -\frac{2}{3}(x-6)\\y + 3 = -\frac{2}{3}(x-6)

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Select the fraction that is equivalent to 2/3
WITCHER [35]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Can someone help me plz!!! I would appreciate it ❤️
kolezko [41]

Answer:

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7 0
3 years ago
Given Sn=2n^2 - 5n, find
brilliants [131]

Answer:

a) -3

b) 117

c) 100

Step-by-step explanation:

(a) 2(1)²-5(1)

1²= 1

2×1= 2

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(b) 2(9)²-5(9)

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(c) 2(4)²-5(4) +2(8)²-5(4)

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hope it helps!

6 0
3 years ago
Select the best answer for the question.
Marat540 [252]

The answer of this question is 42


3 0
3 years ago
Please help! Greatly appreciated sorry for really bad quality
Degger [83]
The first answer.

Point P is at (50,-40) the distance from Q to P is 80 units which you can find by subtracting the x of Q (-30) from the x of P (50).
50-(-30)=80
It then tells you point R is vertically above point Q so you know your x value for R will be the same as Q.
Add your distance from Q to P of 80 units to the y value of Q because you are traveling up.
-40+80=40
R will have a point of (-30,40) and a distance of 80 units
7 0
3 years ago
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