Which expression is equivalent to 14 x 14? 2^2 2^14 14^2 14^14

Suppose you want to have $400,000 for retirement in 30 years. Your account earns 4% interest.

Ne4ueva [31]

Answer:

if he wants to have $400000 on gis bank in 30 years at 4 %rate then he needs to deposit $15151.5 per month

5 0

3 years ago

CAN SOMEONE HELP!!!! This is technically HIGHSCHOOL not middle.

Savatey [412]

Answer:

0.45

Explanation:

The probability that the rainfall for the year is less than 8 inches is equal to the area under the curve of the probability density function to the left of 8 inches.

I attached a graph with the squares that cover that area in red.

There are 7 complete, or almost complete, red squares and 4 triangles.

For estimation purposes, you can count each triangle as half a square.

Thus, consider 7 + 4/2 = 7 + 2 = 9 squares.

Since the area of each square on the grid is 0.05, the area o 9 squares is:

9 × 0.05 = 0.45

Hence, your estimate of the probability that the rainfall for this year is less than 8 inches is 0.45.

4 0

3 years ago

There is 9 players on one team and 8 on the other, both teams give each other high-fives, how many high fives took place?

AnnyKZ [126]

Total high fives is 72

Explanation:

Given:

Number of players in team 1 = 9

Number of players in team 2 = 8

A high-five occurs between 2 people of each team

1 player will give high five to 8 players

So, 9 players will give high five to 9 X 8 players

Total high fives = 72

Therefore, total high fives is 72

8 0

3 years ago

HELP PLEASE PLEASE PLEASE FAKE ANSWERS WILL BE REPORTED

slega [8]

Answer:

can you tell us the question please sorry it's hard to read.

3 0

3 years ago

Use the sample data and confidence level given below to complete parts (a) through (d). A drug is used to help prevent blood c

Alla [95]

Answer:

a) $\hat p=\frac{148}{4167}=0.036$

b) $0.0355 - 1.96\sqrt{\frac{0.036(1-0.036)}{4167}}=0.030$

$0.0355 + 1.96\sqrt{\frac{0.036(1-0.036)}{4167}}=0.041$

Step-by-step explanation:

The sample proportion have the following distribution

$\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Part a

The estimated proportion for this case can be calculated like this:

$\hat p=\frac{148}{4167}=0.036$

Part b

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

Replacing we got:

$0.0355 - 1.96\sqrt{\frac{0.036(1-0.036)}{4167}}=0.030$

$0.0355 + 1.96\sqrt{\frac{0.036(1-0.036)}{4167}}=0.041$

8 0

4 years ago