1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Margaret [11]
2 years ago
5

One of the solutions to the equation x² - 5x-24 = 0 is 8. What is the other solution?​

Mathematics
2 answers:
ehidna [41]2 years ago
7 0
X^2 - 5x - 24
(X - 8)(x + 3)
X = 8 and x = -3
Therefore, the other solution is -3.
creativ13 [48]2 years ago
6 0

Answer:

-3

Step-by-step explanation:

This is a quadratic equation. Therefore, one way we can solve this is by using the quadratic formula, \frac{-b+\sqrt{b^2-4ac} }{2a} and \frac{-b-\sqrt{b^2-4ac} }{2a}.

a, b, and c represent the coefficients in our equation x^2-5x-24=0. a represents the coefficient of the term with degree of 2, which is 1. b represents the coefficient of the term with degree of 1, which is -5. c represents the coefficient of the term with degree of 0, which is -24.

Let us plug them in the equation! Let us start with this one: \frac{-b+\sqrt{b^2-4ac} }{2a}

\frac{5+\sqrt{(-5)^2-4*1*(-24)} }{2} =\\\frac{5+\sqrt{25+96} }{2} =\\\frac{5+\sqrt{121} }{2} =\\\frac{5+11}{2} =\\\frac{16}{2} =\\8

Oops! We are looking for the other solution. Let us plug in the values in this equation instead: \frac{-b-\sqrt{b^2-4ac} }{2a}

\frac{5-\sqrt{(-5)^2-4*1*(-24)} }{2} =\\\frac{5-\sqrt{25+96} }{2} =\\\frac{5-\sqrt{121} }{2} =\\\frac{5-11}{2} =\\\frac{-6}{2} =\\-3

<em>I hope this helps! Let me know if you have any questions :)</em>

You might be interested in
A salesperson earns $320 per week plus 8% of her weekly sales. The expression representing her earnings is 320 + 0.08x. Which of
Arturiano [62]

Answer:

Here, x represents the weekly sale

As per the statement:

A salesperson earns $320 per week plus 8% of her weekly sales.

"8% of her weekly sales" means \frac{8}{100}x = 0.08x

then;

the expression which represents her earning = 320+0.08x

"At least" means "\geq"

then;

the sales necessary for the salesperson to earn at least $1000 in the one week

⇒320+0.08x\geq 1000

Subtract 320 from both sides we have;

0.08x\geq 680

Divide both sides by 0.08 we get:

x\geq 8500

Therefore, the sales necessary for the salesperson to earn at least $1000 in the one week is: greater than or equal to $8500 i.e  x\geq 8500

6 0
3 years ago
Solve pls brainliest
Lyrx [107]

Answer:

a. 9m/s × 27s = 243m

b. -6°C/3hrs = -2°C/hr

8 0
2 years ago
Use polar coordinates to find the limit. [if (r, θ) are polar coordinates of the point (x, y) with r ≥ 0, note that r → 0 as (x,
Lady bird [3.3K]
Wages wages wages wages wages wages wages wages wages wages wages 
3 0
3 years ago
James is reading a book that is 1400 pages he will read the same number of pages each day if he reads the book in 7 days how man
Novay_Z [31]
He will read 200 pages a day.
7 0
3 years ago
Read 2 more answers
HELP???? PLEASE!!! HELP?????
saul85 [17]
.55 is the answer. I hope this helped a great deal!
5 0
3 years ago
Other questions:
  • PLEASE ANSWER + BRAINLIEST!!
    8·1 answer
  • Please help I don’t understand
    9·1 answer
  • I already did 1,2 I just need help with three I’ll give u the best rating if u can answer it ❤️
    7·1 answer
  • 52=4z <br> HELP PLS ILL MARK BRAINLIEST
    12·1 answer
  • Solve for x please:<br>x-2=17
    12·2 answers
  • The hypotenuse of a right triangle is 12, and one of the legs is 4, what’s the missing leg
    15·1 answer
  • Rewrite the expression by using grouping symbols.
    12·1 answer
  • A square has an area of 49in^2. If the same amount is added to the length and removed from the width, the resulting rectangle ha
    14·1 answer
  • Pleaseeee hELPppP correct answer
    7·1 answer
  • Jacob spent $40 dollars on supplies to make 100 shirts for a baseball team fundraiser. Solve the inequality to help him decide h
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!