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2 years ago

10

Robert bough 3/4 pound of grapes and divided them into 6 equal portions.

1 answer:

insens350 [35]2 years ago

4 0

Answer: The answer should be 0.125

Step-by-step explanation:

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Please help! what is the polar equation r = -5 theta in parametric form?<br><br> thank you!

Rudiy27

Use these equations when converting polar equations to parametric equations:

$x=r\cos\theta$

$y=r\sin\theta$

We know that $r=5\theta$ , so substitute that into both equations for x and y.

$x=5\theta\cos\theta$

$y=5\theta\sin\theta$

Now, replace $\theta$ with any variable that you want to represent the parametric equations in. I'll use the standard variable, $t$

$x=5t\cos t$

$y=5t\sin t$

Thus, $r=5\theta$ represented in parametric form is:

$(x,y)=(5t\cos t, 5t \sin t)$

Let me know if you need any clarifications, thanks!

~ Padoru

4 0

3 years ago

Find the distance between the points (-2, 4) and (5, 4). <br> 3<br><br> 7 <br><br> 8

Lina20 [59]

Try this solution:
distance= $\sqrt{(5-(-2)^2+(4-4)^2} = \sqrt{49} =7.$

answer: 7

8 0

3 years ago

Can anyone help me with this pls? i have no idea what im doing

Musya8 [376]

$h(11)=-20+11\cdot11=-20+121=-101$

8 0

2 years ago

A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe

adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

$\frac{dC}{dt}=Ci*Qi-Co*Qo$

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

$\frac{dC}{dt}=-Co*Qo$

Rearranging the equation, it becomes

$\frac{dC}{C}=-Qo*dt$

Integrating both sides

$\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}$

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

$C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\$

The final equation for the concentration of salt at any given time is

$C=exp^{-3*t-0.693}$

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

$C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}= -\frac{-0.266}{3}=0.088$

5 0

2 years ago

Use yes or no Can you please help me

Gemiola [76]

The answer Yes, yes, no

7 0

2 years ago