Let
be the number of hours worked at Job A and
the number of hours at Job B. Then

and

From the first equation,

and substituting this into the second gives



Answer:
i think A if not sorry
Step-by-step explanation:
1900 - 1300 = 6,000 more website hits on Tuesday.
There are six possibilities, and one of those possibilities is a 3.
Therefore, the probability of rolling a 3 is: 1/6.
Then what’s the question?