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Genrish500 [490]
3 years ago
7

Write a loop that prints each country's population in country_pop. Sample output with input:

Computers and Technology
1 answer:
Nostrana [21]3 years ago
4 0

Answer:

  1. country_pop = {
  2.    'China': 1365830000,
  3.    'India': 1247220000,
  4.    'United States': 318463000,  
  5.    'Indonesia': 252164800
  6. }  
  7. for key in country_pop:
  8.    print(key + " has " + str(country_pop[key]) + " people")

Explanation:

The solution code is written in Python 3.

Given a dictionary, country_pop with data that includes four country along with their respective population (Line 1-6). We can use for in loop structure to traverse through each of the key (country) in the dictionary and print their respective population value (Line 7-8). The general loop structure through is as follow:

                    for key in dict:

                         do something

One key will be addressed for each round of loop and we can use that key to extract the corresponding value of the key (e.g. country_pop[key]) and print it out.

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Explanation:

Surface web is also called visible web is a part of world wide web that can be easily searchable using search engines as its contents are indexed by the search engines such as Google and its contents are accessible by public using standard web browsers. So a is not a suitable choice.

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3 years ago
Using the C language, write a function that accepts two parameters: a string of characters and a single character. The function
Sav [38]

Answer:

#include <stdio.h>

void interchangeCase(char phrase[],char c){

  for(int i=0;phrase[i]!='\0';i++){

      if(phrase[i]==c){

          if(phrase[i]>='A' && phrase[i]<='Z')

              phrase[i]+=32;

          else

              phrase[i]-=32;      

      }

  }

}

int main(){

  char c1[]="Eevee";

  interchangeCase(c1,'e');

  printf("%s\n",c1);

  char c2[]="Eevee";

  interchangeCase(c2,'E');

  printf("%s\n",c2);    

}

Explanation:

  • Create a function called interchangeCase that takes the phrase and c as parameters.
  • Run a for loop that runs until the end of phrase and check whether the selected character is found or not using an if statement.
  • If the character is upper-case alphabet, change it to lower-case alphabet and otherwise do the vice versa.
  • Inside the main function, test the program and display the results.
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