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artcher [175]
3 years ago
8

Q. Which protocol would best serve to authorize users to access directory services?

Computers and Technology
1 answer:
Arlecino [84]3 years ago
6 0

Answer:

Lightweight directory access protocol (LDAP)

Explanation:

Lightweight directory access protocol is a protocol that provides a common open protocol for interfacing and querying a directory service information given by a network operating system. LDAP is an application layer protocol that uses port number 389 via tcp and udp. LDAP queries are transmitted in text and allows for all or some data be queried anonymously.

Lightweight directory access protocol, ordinarily does not require user authentication connection, but this can be configured to ask for user credentials.

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A notebook computer usually is more expensive than a desktop computer with the same capabilities because it ____.
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Because it is more portable.
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What word is used today to refer to network-connected hardware devices?.
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In two to three sentences, describe one tool used in project management and why it is used.
Ksenya-84 [330]

Answer:

Gantt Chart

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Homework 8 Matlab Write a function called fibonacciMatrix. It should have three inputs, col1, col2, and n. col1 and col2 are ver
Amiraneli [1.4K]

In this exercise we have to use the knowledge in computational language in python to write the following code:

We have the code can be found in the attached image.

So in an easier way we have that the code is:

<em>function v = myfib(n,v)</em>

<em>if nargin==1</em>

<em>    v = myfib(n-1,[0,1]);</em>

<em>elseif n>1</em>

<em>    v = myfib(n-1,[v,v(end-1)+v(end)]);</em>

<em>end</em>

<em>end</em>

<em>function v = myfib(n,v)</em>

<em>if nargin==1</em>

<em>    v = myfib(n-1,[0,1]);</em>

<em>elseif n>1</em>

<em>    v = myfib(n-1,[v,v(end-1)+v(end)]);</em>

<em>elseif n<1</em>

<em>    v = 0;</em>

<em>end</em>

<em>function [n] = abcd(x)</em>

<em>if (x == 1 || x==0)</em>

<em>    n = x; </em>

<em>    return</em>

<em>else</em>

<em>    n = abcd(x-1) + abcd(x-2);</em>

<em>end</em>

<em>end</em>

<em>fibonacci = [0 1];</em>

<em>for i = 1:n-2</em>

<em>    fibonacci = [fibonacci fibonacci(end)+fibonacci(end-1)];</em>

<em>end</em>

<em>>> myfib(8)</em>

<em>ans =</em>

<em>    0    1    1    2    3    5    8   13</em>

<em>>> myfib(10)</em>

<em>ans =</em>

<em>    0    1    1    2    3    5    8   13   21   34</em>

See more about python at  brainly.com/question/18502436

8 0
2 years ago
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