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3 years ago

Estimate each elapsed time to the nearest hour

1 answer:

3 0

1. 1:38 AM to 4:38 AM is 3 hours, 4:38 AM to 4:50 AM is 12 mins. This means that total time elapsed is 3 hours and 12 mins. Rounding to nearest hour gives 3 hours.

2. I assume you mean 11:49 AM. 11:49 AM to 6:49 PM is 7 hours. 6:49 PM to 7:12 PM is 23 mins. Total time is 7 hours 23 mins, or 7 hours to the nearest hour.

3. 2:25 PM to 3:25 PM is 1 hour, 3:25 PM to 3:35 PM is 10 mins. Total time is 1 hour 10 mins or 1 hour to the nearest hour.

4. 8:25 AM to 10:25 AM is 2 hours. 10:25 AM to 10:52 AM is 27 mins. Total time is 2 hours 27 mins or 2 hours to the nearest hour.

The trick is to count the number of hours first, then count the number of minutes remaining.

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The value of X is: A 11.3 B 8 C 16

diamong [38]

Answer:

x ≈ 11.3

Step-by-step explanation:

Using the sine ratio in the right triangle

sin45° = $\frac{opposite}{hypotenuse}$ = $\frac{8}{x}$ ( multiply both sides by x )

x × sin45° = 8 ( divide both sides by sin45° )

x = $\frac{8}{sin45}$ ≈ 11.3

6 0

3 years ago

Ow these steps using the algebra tiles to solve the equation −5x + (−2) = −2x + 4.

Andrews [41]

Answer: I got x=-2

Step-by-step explanation:

3 0

4 years ago

Solve for x. Enter the solutions from least to greatest. . (x - 10)2 - 1 = 0

lawyer [7]

2x -20 -1 =0
2x -21=0
2x=21
x= 10.5

4 0

3 years ago

Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed

vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 11-1 = 10$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have $T = 1.812$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{4}{\sqrt{11}} = 1.2060$

Now, we multiply T and s

$M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8$ cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

$L = 97 + 2.19 = 99.19 = 99.2$ cm

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm).

7 0

3 years ago

In a survey, a group of students were asked to name their favorite subject. There were 20 students who chose "other" subjects. H

mixer [17]

Other = 20 students which equals 25 percent, because math and english sum to 75 percent. if 25* 4 is 100, then you can do 20*4 to get 80, which is how many students participated

5 0

4 years ago