Answer:
p(x)= (x+1)(x+2)(x-3)(x-1)
then,multiplying two two terms
(x^2 +2x+x+2)(x^2-x-3x+3)
(x^2+3x+2)(x^2-4x+3)
x^4- 4x^3+3x^2 +3x^3-12x^2+9x+2x^2-8x+6)
x^4-x^3-7x^2+x+6
Answer:
Ah yes, one of my favorite topics.
Step 1: Which ever fraction comes first, you will solve it first. For this question, focus on doing 
first. Afterwards, do 
Step 2: First one equals to 1.125. Next, find the LCD (lowest common dominator, which is 10). 
Step 3: 1.125+3/10
To answer this question, you need to know that a quarter is worth $0.25 and dimes worth $0.10. In this case, the total number of money that made from quarters and dimes is $2.80
With Q=quarter and D=dime, then the equation should be:
2.80= 0.25 Q + 0.10 D
The condition that needs to be fulfilled in this case is that the quarter should be 8 more than dimes. Then you need to find out the highest possible number of the quarter and lowest possible number of the dimes.
If you divide 2.8 with 0.25 you will found it will be 11.2 but 11 quarter will result with 0.05 value which you cannot remove, so the highest possible of the quarter should be 10.
If the highest possible of the quarter is 10, then the lowest possible of dimes should be:
2.8= 0.25(10) + 0.10D
0.10D= 0.3
D=3
Since 10-3 is 7, then it is not possible for the quarter to be 8 more than the dimes.
Answer:
Each point does NOT ALWAYS give the same amount of tickets.
11 point would most likely give 90 tickets.
Step-by-step explanation:
2 points give 18 tickets = 9 tickets per point
3 points give 27 tickets = 9 tickets per point
9 points give 72 tickets = 8 tickets per point
You can add the 2 point value with the 9 point values to find out many point it takes to get to 90 tickets.
18(2 tickets) + 72(9 tickets) = 90(11 tickets)
