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BaLLatris [955]
3 years ago
12

if cotθ= 7 and π < θ < 2π , sketch the angle θ and find the value of the other five trig functions

Mathematics
1 answer:
valina [46]3 years ago
8 0

\cot\theta=7, so you immediately get

\dfrac1{\cot\theta}=\boxed{\tan\theta=\dfrac17}

Recall the Pythagorean identity:

\tan^2\theta+1=\sec^2\theta\implies\sec\theta=\pm\sqrt{1-\left(\dfrac17\right)^2}=\pm\dfrac{4\sqrt3}7

and from this we also get cosine for free, since

\dfrac1{\sec\theta}=\cos\theta=\pm\dfrac7{4\sqrt3}

But only one of these can be correct. By definition of tangent,

\tan\theta=\dfrac{\sin\theta}{\cos\theta}

For \theta between π and 2π, we expect \sin\theta to be negative. We konw \tan\theta is positive, which means \cos\theta must also be negative. So we have

\boxed{\cos\theta=\dfrac7{4\sqrt3}}

\boxed{\sec\theta=\dfrac{4\sqrt3}7}

and we can find sine using the tangent:

\tan\theta=\dfrac{\sin\theta}{\cos\theta}\implies\dfrac{\frac7{4\sqrt3}}7=\boxed{\sin\theta=\dfrac1{4\sqrt3}}

and for free we get

\dfrac1{\sin\theta}=\boxed{\csc\theta=4\sqrt3}

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9. Find the volume of the triangular pyramid. (2pts)-10 mI9 m16 m
Makovka662 [10]

Answer:

240 m³

Explanation:

The volume of a pyramid is equal to:

V=\frac{1}{3}\times B\times H

Where B is the area of the base and H is the height of the pyramid.

Then, the base of the pyramid is a triangle, so the area of a triangle is equal to:

B=\frac{b\times h}{2}

Where b is the base of the triangle and h is the height of the triangle. So, replacing b by 16 m and h by 9 m, we get:

B=\frac{16\times9}{2}=\frac{144}{2}=72m^2

Finally, replacing B by 72 m² and H by 10 m, we get that the volume of the pyramid is equal to:

V=\frac{1}{3}\times72\times10=\frac{1}{3}\times720=240m^3

Therefore, the volume is 240 m³

4 0
1 year ago
Am I correct? If so why?
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Answer: its correct

Step-by-step explanation: and its correct cuase its the answer you choose

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Step-by-step explanation:

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