, so you immediately get
Recall the Pythagorean identity:
and from this we also get cosine for free, since
But only one of these can be correct. By definition of tangent,
For between π and 2π, we expect to be negative. We konw is positive, which means must also be negative. So we have
and we can find sine using the tangent:
and for free we get
Answer:
1=15.7
2:31.4
3:12.5
Step-by-step explanation:
1=5×3.14=15.71
2:5×2=10×3.14=31.42
3:39.25÷3.14=12.5
hope this helps
Answer: (a) IV (b) positive (c) (d) C (e)
<u>Step-by-step explanation:</u>
a) - = , which is located in Quadrant IV <em>per the Unit Circle. </em>
b) sec is . Cos is the x-coordinate. The x-coordinate inQuadrant IV is positive.
c) the reference angle is the angle from to 2π =
d) since the angle is below the x-axis and the reference angle is, then the angle is equal to )
e) sec = ⇒ sec = = = =
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Answer: (a) (b) (0, -1) (c) A (d) -1
a) - = - =
b) is on the Unit Circle at (0, -1)
c) sin = which equals on the Unit Circle.
d) sin is the y-coordinate. sin = -1