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BaLLatris [955]
3 years ago
12

if cotθ= 7 and π < θ < 2π , sketch the angle θ and find the value of the other five trig functions

Mathematics
1 answer:
valina [46]3 years ago
8 0

\cot\theta=7, so you immediately get

\dfrac1{\cot\theta}=\boxed{\tan\theta=\dfrac17}

Recall the Pythagorean identity:

\tan^2\theta+1=\sec^2\theta\implies\sec\theta=\pm\sqrt{1-\left(\dfrac17\right)^2}=\pm\dfrac{4\sqrt3}7

and from this we also get cosine for free, since

\dfrac1{\sec\theta}=\cos\theta=\pm\dfrac7{4\sqrt3}

But only one of these can be correct. By definition of tangent,

\tan\theta=\dfrac{\sin\theta}{\cos\theta}

For \theta between π and 2π, we expect \sin\theta to be negative. We konw \tan\theta is positive, which means \cos\theta must also be negative. So we have

\boxed{\cos\theta=\dfrac7{4\sqrt3}}

\boxed{\sec\theta=\dfrac{4\sqrt3}7}

and we can find sine using the tangent:

\tan\theta=\dfrac{\sin\theta}{\cos\theta}\implies\dfrac{\frac7{4\sqrt3}}7=\boxed{\sin\theta=\dfrac1{4\sqrt3}}

and for free we get

\dfrac1{\sin\theta}=\boxed{\csc\theta=4\sqrt3}

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Please help I’m so confused 25 points and brainliest!!
il63 [147K]

Answer:

1=15.7

2:31.4

3:12.5

Step-by-step explanation:

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HELP WITH THESE QUESTIONS PART 2.
polet [3.4K]

Answer: (a) IV (b) positive (c) \frac{\pi}{4} (d) C (e) \sqrt{2}

<u>Step-by-step explanation:</u>

a) \frac{15\pi}{4} - \frac{8\pi}{4} = \frac{7\pi}{4}, which is located in Quadrant IV <em>per the Unit Circle.  </em>

b) sec is \frac{1}{cos}. Cos is the x-coordinate.  The x-coordinate inQuadrant IV is positive.

c) the reference angle is the angle from \frac{7\pi}{4} to 2π = \frac{\pi}{4}

d) since the angle is below the x-axis and the reference angle is\frac{\pi}{4}, then the angle is equal to -sec(\frac{\pi}{4})

e) sec = \frac{1}{cos}   ⇒   sec \frac{7\pi}{4} = \frac{2}{\sqrt{2} } = \frac{2}{\sqrt{2} }(\frac{\sqrt{2}} {\sqrt{2}}) = \frac{2\sqrt{2} }{2} = \sqrt{2}

**********************************************************

Answer: (a) \frac{3\pi}{2} (b) (0, -1) (c) A (d) -1

<u>Step-by-step explanation:</u>

a) \frac{11\pi}{2} - \frac{4\pi}{2} = \frac{7\pi}{2} - \frac{11\pi}{2} = \frac{3\pi}{2}

b) \frac{3\pi}{2} is on the Unit Circle at (0, -1)

c) sin = \frac{opposite}{hypotenuse} which equals \frac{y}{r} on the Unit Circle.

d) sin is the y-coordinate. sin (\frac{3\pi}{2}) = -1

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I think she would have $1,058.07
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