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kotegsom [21]
3 years ago
14

-ax+3b>5 solve for x

Mathematics
1 answer:
Dmitry [639]3 years ago
3 0

-ax+3b > 5\qquad|\text{subtract 3b from both sides}\\\\-ax > -3b+5\qquad|\text{change the signs}\\\\ax < 3b-5\qquad|\text{divide both sides by a}\\\\\text{if}\ a < 0,\text{ then}\ x > \dfrac{3b-5}{a}\\\\\text{if}\ a > 0,\text{ then}\ x < \dfrac{3b-5}{a}

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