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kotegsom [21]
3 years ago
14

-ax+3b>5 solve for x

Mathematics
1 answer:
Dmitry [639]3 years ago
3 0

-ax+3b > 5\qquad|\text{subtract 3b from both sides}\\\\-ax > -3b+5\qquad|\text{change the signs}\\\\ax < 3b-5\qquad|\text{divide both sides by a}\\\\\text{if}\ a < 0,\text{ then}\ x > \dfrac{3b-5}{a}\\\\\text{if}\ a > 0,\text{ then}\ x < \dfrac{3b-5}{a}

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Step-by-step explanation:

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In certain county, the number of charter schools is 4 less than twice the numbervof alternative schools. We know that there are
Vitek1552 [10]
1. Let's call the number of carter school: "x" and "y" the number of alternative school.  Then, you have that:

 - T<span>he number of charter schools is 4 less than twice the number of alternative schools.
</span> - T<span>here are 48 charter schools in the country.

 2. So, you have:

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3 years ago
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alina1380 [7]

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2 years ago
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bagirrra123 [75]

\huge\textbf{Hey there!}

\huge\boxed{\textbf{5m = 10}}\\\\\large\textbf{DIVIDE 5 to BOTH SIDES}\\\\\huge\boxed{\mathbf{\dfrac{5m}{5} = \dfrac{10}{5}}}\\\\\large\textbf{CANCEL out: }\bold{\dfrac{5}{5}}\large\textbf{ because it gives you 1}\\\large\textbf{KEEP: }\rm{\bf \dfrac{10}{5}}\large\textbf{ because it gives you the m-value}\\\large\textbf{NEW EQUATION: m = }\bf \rm{\dfrac{10}{5}}\\\\\large\textbf{SIMPLIFY IT!}\\\huge\boxed{\mathbf{m = 2}}\\\large\textbf{Therefore, your answer is: \huge\boxed{\mathsf{m = 2}}}\huge\checkmark

\huge\textbf{Good luck on your assignment \&}\\\huge\textbf{enjoy your day!}

<h2>~\mathfrak{Amphitrite1040:)}</h2>
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