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kotegsom [21]
4 years ago
14

-ax+3b>5 solve for x

Mathematics
1 answer:
Dmitry [639]4 years ago
3 0

-ax+3b > 5\qquad|\text{subtract 3b from both sides}\\\\-ax > -3b+5\qquad|\text{change the signs}\\\\ax < 3b-5\qquad|\text{divide both sides by a}\\\\\text{if}\ a < 0,\text{ then}\ x > \dfrac{3b-5}{a}\\\\\text{if}\ a > 0,\text{ then}\ x < \dfrac{3b-5}{a}

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22-3(4)<br> How do I answer this question?
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Answer:

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Step-by-step explanation:

22-3=19

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5 0
3 years ago
Read 2 more answers
Please give the answer
sweet [91]

The function can be solved as follows:

  • f(6 + 4) = 25
  • f(6) - f(4) = 20
  • f(6 - 4) = 1
  • f(6) - f(4) = 6
  • f(6) . f(4) = 91

<h3>How to solve function?</h3>

f(x) = 3x - 5

Therefore, the function can be solved as follows:

f(6 + 4) = f(10) = 3(10) - 5 = 25

f(6) + f(4) = 3(6) - 5 + (3(4) - 5)

f(6) - f(4) = 13 + 7

f(6) - f(4) = 20

f(6 - 4) = f(2) = 3(2) - 5 = 6 - 5 = 1

f(6) - f(4) = 3(6) - 5 - (3(4) - 5)

f(6) - f(4) = 18 - 5  - (12 - 5)

f(6) - f(4) = 13 - 7

f(6) - f(4) = 6

f(6.4) = f(24) = 3(24) - 5 = 72 - 5 = 67

f(6) . f(4) = (3(6) - 5 ) (3(4) - 5)

f(6) . f(4) = (18 - 5)(12 - 5)

f(6) . f(4) = (13)(7) = 91

learn more on function here: brainly.com/question/9390144

#SPJ1

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Step-by-step explanation:

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Which of the following illustrates the truth value of the given conditional statement?
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Answer:

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Step-by-step explanation:

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