Question

-ax+3b>5 solve for x

Answer 1

$-ax+3b > 5\qquad|\text{subtract 3b from both sides}\\\\-ax > -3b+5\qquad|\text{change the signs}\\\\ax < 3b-5\qquad|\text{divide both sides by a}\\\\\text{if}\ a < 0,\text{ then}\ x > \dfrac{3b-5}{a}\\\\\text{if}\ a > 0,\text{ then}\ x < \dfrac{3b-5}{a}$