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2 years ago

Using the triangle below, set up and solve an equation in order to find the value of x.

Mathematics

2 answers:

Colt1911 [192]2 years ago

6 0

Answer:

90+15x+8x-2=180

Step-by-step explanation:

answer is 4

have a great day love!

bogdanovich [222]2 years ago

3 0

Answer:

The answer is 4

90+15x+8x-2=180

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suppose that you have 3000$ to invest. which investment yields the greater return over a 10 year period: 8.04% compounded daily

Ksenya-84 [330]

Answer: Option A: 8.04% compounded daily

<u>Step-by-step explanation:</u>

$A = P\bigg(1+\dfrac{r}{n}\bigg)^{nt}\qquad where\\\\\bullet A = \text{accrued amount (principal plus interest earned)}\\\bullet P = \text{principal (amount invested)}\\\bullet r = \text{rate (in decimal form)}\\\bullet n=\text{number of times compounded in one year}\\\bullet t=\text{time (number of years)}\\\\\\Option\ A:\\A = \text{unknown}\\P=3000\\r=8.04\%\rightarrow 0.0804\\n=\text{daily}\rightarrow 365\\t=10\\\\A=3000\bigg(1+\dfrac{0.0804}{365}\bigg)^{365\times 10}\\\\.\ =\$ 6,702.79$

$Option\ B:\\A = \text{unknown}\\P=3000\\r=8.1\%\rightarrow 0.081\\n=\text{quarterly}\rightarrow 4\\t=10\\\\A=3000\bigg(1+\dfrac{0.081}{4}\bigg)^{4\times 10}\\\\.\ =\$ 6,689.37$

Option A results in the greater amount of money.

7 0

3 years ago

(Inequalities) what do you have to do when multiplying or dividing by a negative number?

Rashid [163]

Answer:

When we multiply or divide by a negative to solve an inequality, it's the same as multiplying or dividing by a negative to solve a regular equation! Just remember to multiply or divide both sides by the same quantity, then simplify! Remember, when multiplying or dividing by a negative <u>YOU MUST FLIP THE INEQUALITY SIGN.</u>

Step-by-step explanation:

You are welcome.

And I hope this helps. :)

4 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%2F27%7D%20%3D%20-2%2F3" id="TexFormula1" title="\sqrt[3]{-8/27} = -2/3" al

sasho [114]

The equation is true because both sides are identical.

5 0

3 years ago

Are the functions f(x) = (x^2-1)/(x-1) and g(x)= x+1 equal for all x?

Vinvika [58]

$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\$

$\bf f(x)=\cfrac{x^2-1}{x-1}\implies f(x)=\cfrac{x^2-1^2}{x-1}\implies f(x)=\cfrac{(\underline{x-1})(x+1)}{\underline{x-1}}
\\\\\\
f(x)=x+1\qquad \qquad \qquad \qquad \qquad g(x)=x+1\\\\
-------------------------------\\\\
\textit{they're, kinda, except that, when x = 1}
\\\\\\
g(x)=(1)+1\implies g(x)=2
\\\\\\
f(x)=\cfrac{(1)^2-1}{(1)-1}\implies f(x)=\cfrac{0}{0}\impliedby und efined$

7 0

3 years ago

Find the value of x. Round to the nearest tenth of a foot.

Reptile [31]

Answer:

Step-by-step explanation:

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3 years ago