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elena55 [62]
3 years ago
13

Annie brought nickels, dimes and quarters to the store. If she has at least one of every coin, they add up to $1.00, and Annie h

as 15 coins total, what is the probability that one coin at random is a nickel? Lots of points, and will give brainliest! Please help!
Mathematics
2 answers:
mojhsa [17]3 years ago
5 0
She has 1 quarter, 1 dime and 13 nickels. So the probability that one coin at random is a nickel is 13/15.

My work:

1$= 100

1 quarter=25

1 dime=10

1+1+13= 15

25×1= 25

10×1= 10

5×13= 65

65+25+10= 100
a_sh-v [17]3 years ago
3 0

Answer:

13/15

Step-by-step explanation:

she has at least one of every coin, they add up to $1.00, and Annie has 15 coins total

15-1 nickel -1 dimes -1 quarter=12 coins

$1-0.05-0.1-0.25=$0.6

cuz 12*0.05=0.6

13 nickels + 1 dimes + 1 quarter is the only possible combo.

pro (1 coin is nickel)=no of nickels/total no. of coins

=13/15

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<span>If this is an isosceles triangle, then it has two 45 degree angles corresponding to two legs of equal length.  Orient the base of this triangle so that it's horizontal, and represent its length by b.  Let h represent the height of the triangle.  Then the area of this right triangle is 50 square inches = (1/2)(b)(h), or A = (b/2)h = 50 in^2.   

Due to the 45 degree angles, the height of this triangle is equal to half the base, or h = b/2.  Thus, (b/2)h = 50 becomes (b/2)(b/2) = 50, or b^2=200. Thus, b = 10sqrt(2), and h=(1/2)(10 sqrt(2)), or h = 5sqrt(2).

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