<span>If this is an isosceles triangle, then it has two 45 degree angles corresponding to two legs of equal length. Orient the base of this triangle so that it's horizontal, and represent its length by b. Let h represent the height of the triangle. Then the area of this right triangle is 50 square inches = (1/2)(b)(h), or A = (b/2)h = 50 in^2.
Due to the 45 degree angles, the height of this triangle is equal to half the base, or h = b/2. Thus, (b/2)h = 50 becomes (b/2)(b/2) = 50, or b^2=200. Thus, b = 10sqrt(2), and h=(1/2)(10 sqrt(2)), or h = 5sqrt(2).
The length of one of the legs is the sqrt of [5sqrt(2)]^2+[5sqrt(2)]^2, or
sqrt(25(2)+25(2)) = sqrt(100) = 10.
</span>
Answer:
y= 1/12(x-0)^2+0
this answer works as an upward parabola
Step-by-step explanation:
- The formula for a veritcal parabola is y=1/4p(x-h)^2+k
- (h,k)= coordinates of the vertex of the parabola
- p= absolute value of the distance from the vertex to the focus/directrix
- In this problem, it is given that the vertex is at the origin (0,0) and the focus (the bulb), is 3 centimeters away from the vertex.
- Now, you know the values of the variables. Fill in the values
- FROM THE FORMULA: 1/4p turns into 1/12 since p is 3.
- (x-h)^2+k turns into (x-0)^2+0, since h and k where the values of the vertex which was 0,0
- once all the variables are given values (except x and y) you have made your equation!
- The answer is y=1/12(x-0)^2+0
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X>_ 0
If you don’t understand that then x is greater than or equal to 0
I can’t see the entire question, but i’m going to go out on a limb and say it’s divide, y-value, x-value
The answers to the questions are:
1. The confidence level is 99 percent.
2. We have to conclude that there is no sufficient evidence available to support this claim because the Confidence interval contains 75 sec.
<h3>How to solve for the confidence level</h3>
1. The confidence level here should be
1- 0.01 = 0.99
= 99 percent
Given that, 99% confidence interval for population mean (μ) is (-34.1 sec u< u < 264.1 ) seconds.
We are to test the claim that the population mean is greater than 75 sec.
2.
The given confidence interval contains the value of 75 sec, so there is not sufficient evidence to support the claim that the mean is greater than 75 sec.
Read more on confidence interval here:
brainly.com/question/20309162
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