If you flip the five coins, and the probability of one coin being "tails" is 0.50, what is the probability of getting "tails" on
1 answer:
Answer: 0.03125
Step-by-step explanation:
We know that the probability of getting a tail , we toss a fair coin = 0.5
Given : Total number of trials = 5
Using binomial probability formula :
, where P(x) is the probability of getting success in x trails, n is total number of trials and p is the probability of getting success in each trial.
The probability of getting "tails" on all five coins :_
Hence, the probability of getting "tails" on all five coins =0.03125
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Answer:
Step-by-step explanation:
Hello!
In a day a total of n= 8000 passangers arrived to Phoenix.
1400 of these passangers <u>final destination was Phoenix. (A)</u>
The remaining 6600 passangers were all taking c<u>onnection flights to other cities. (B)</u>
Due to several flights being late, 430 connecting passengers <u>missed their connecting flight and were delayed in Phoenix. (C)</u>
Of these 430 delayed passengers, 75 were <u>delayed overnight. (D)</u>
If there was one passenger chosend at random:
a) You have to calculate the probability of this passegners final destination to be Phoenix. Symbolically: P(A)
To calculate this probability you have to divide the number of passengers whose final destination was Phoenix by the total number of pasengers:
b) The passangers whose final destination was not phoenix are those taking connection flights, the probability of this event, called B, is calculated dividing the total of connecting passengers by the total of passengers:
c) You need to calculate the probability of "the passenger was connecting and missed the connecting flight"
The amount of passengers that fit this situation are 430 of 8000, so the probability is calculated as:
d) Of all 6600 connecting passengers, only 430 missend the flight wich means that 6170 took the connecting flight, the probability of this event "E" is
e) The passenger either had Phoenix as a final destination or was delayed overnight, symbolically:
P(A∪D) = P(A) + P(D) - P(A∩D)
The probability of the passenger being delayed overnight is:
The events "A" and "D" are mutually exclusive, this means that they cannot occur both at the same time, so their intersection is void, P(A∩D)= ∅
Then
P(A∪D) = P(A) + P(D) = 0.175 + 0.009= 0.184
f) If using the same data we turn this event into a binomial variable were our success will be "the passenger missed his flight and was delayed overnight" with probability p=0.009 and the sample n= 50
Let's say that the airline should be worried if more than half of the surveyed passengers were delayed overnight then:
P(X>25)= 1 - P(X ≤ 25) = 1 - 0.999999 = 0.000001
The probability of most of the surveyed passenger were delayed overnight is too low so the company should not be worried.
I hope it helps!