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Kryger [21]
4 years ago
10

Which set of statements would describe a parallelogram that can always be classified as a rhombus? I. Diagonals are perpendicula

r bisectors of each other. II. Diagonals bisect the angles from which they are drawn. III. Diagonals form four congruent isosceles right triangles. 1. I and II 2. I and III 3. II and III 4. I, II, and III
Mathematics
1 answer:
trasher [3.6K]4 years ago
4 0

Answer:

1. I, II,

Step-by-step explanation:

<em>I. Diagonals are perpendicular bisectors of each other  </em>

Yes, because 4 sides are congruent so it makes the two diagonals perpendicular bisectors

<em>II. Diagonals bisect the angles from which they are drawn </em>

Yes, That is the property of the diagonal!

<em> III. Diagonals form four congruent isosceles right triangles. </em>

No, only two pairs of right triangles are congruent and sometime the side of each pair are different to each other.

Hence, we choose I and II

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Which expression has a solution of 36, if w = 9?<br><br> 7 w<br> 4 w<br> 6 w<br> 5 w
Anon25 [30]

Answer:

4w.

Step-by-step explanation:

Replace w with 9.

7(9)=63

4(9)=36

6(9)=54

5(9)=45

Therefore the answer is 4w.

7 0
3 years ago
Read 2 more answers
-12 = -5(x - 3) ......​
Gnoma [55]

Answer:

x = 27/5

Step-by-step explanation:

Step 1: Write equation

-12 = -5(x - 3)

Step 2: Solve for <em>x</em>

  1. Distribute -5: -12 = -5x + 15
  2. Subtract 15 on both sides: -27 = -5x
  3. Divide both sides by -5: x = 27/5

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

-12 = -5(27/5 - 3)

-12 = -5(12/5)

-12 = -12

4 0
3 years ago
Read 2 more answers
Help maybe , I appreciate it ???
algol [13]
The answer is 48 because if a right angle is 90 degrees and angle one 42 then you do 90-42 and you get 48 for angle 2.
3 0
3 years ago
Please help !!!
-BARSIC- [3]

I know the parabola will open downward because the leading coefficient of the equation, being -5, is negative/less than zero.

5 0
3 years ago
Use the following function rule to find h(w–5). Simplify your answer.<br> h(y)=y²–y–5<br> h(w–5)=
Dima020 [189]

The value of the function is h(w - 5) = w^2 - 11w +25

<h3>How to determine the function?</h3>

The function is given as:

h(y) = y^2 - y - 5

Substitute w - 5 for y

h(w - 5) = (w - 5)^2 - (w - 5) - 5

Expand the equation

h(w - 5) = w^2 - 10w + 25 - w + 5 - 5

Evaluate the like terms

h(w - 5) = w^2 - 11w +25

Hence, the value of the function is h(w - 5) = w^2 - 11w +25

Read more about functions at:

brainly.com/question/20379727

#SPJ1

8 0
2 years ago
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