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Kryger [21]
3 years ago
10

Which set of statements would describe a parallelogram that can always be classified as a rhombus? I. Diagonals are perpendicula

r bisectors of each other. II. Diagonals bisect the angles from which they are drawn. III. Diagonals form four congruent isosceles right triangles. 1. I and II 2. I and III 3. II and III 4. I, II, and III
Mathematics
1 answer:
trasher [3.6K]3 years ago
4 0

Answer:

1. I, II,

Step-by-step explanation:

<em>I. Diagonals are perpendicular bisectors of each other  </em>

Yes, because 4 sides are congruent so it makes the two diagonals perpendicular bisectors

<em>II. Diagonals bisect the angles from which they are drawn </em>

Yes, That is the property of the diagonal!

<em> III. Diagonals form four congruent isosceles right triangles. </em>

No, only two pairs of right triangles are congruent and sometime the side of each pair are different to each other.

Hence, we choose I and II

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Determine the margin of error for a 90% confidence interval to estimate the population mean when s = 40 for the sample sizes bel
Ann [662]

Answer:

a) The margin of error for a 90% confidence interval when n = 14 is 18.93.

b) The margin of error for a 90% confidence interval when n=28 is 12.88.

c) The margin of error for a 90% confidence interval when n = 45 is 10.02.

Step-by-step explanation:

The t-distribution is used to solve this question:

a) n = 14

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 14 - 1 = 13

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 13 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.7709

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.7709\frac{40}{\sqrt{14}} = 18.93

In which s is the standard deviation of the sample and n is the size of the sample.

The margin of error for a 90% confidence interval when n = 14 is 18.93.

b) n = 28

27 df, T = 1.7033

M = T\frac{s}{\sqrt{n}} = 1.7033\frac{40}{\sqrt{28}} = 12.88

The margin of error for a 90% confidence interval when n=28 is 12.88.

c) The margin of error for a 90% confidence interval when n = 45 is

44 df, T = 1.6802

M = T\frac{s}{\sqrt{n}} = 1.6802\frac{40}{\sqrt{45}} = 10.02

The margin of error for a 90% confidence interval when n = 45 is 10.02.

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Answer:

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Step-by-step explanation:

We normally think of the ordered pairs as ...

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Another way to think about them is ...

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I find it a little easier to think about the cube of a number, rather than its cube root.

For the y-values given, -2, -1, 0, 2, the points that will be on the graph are ...

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The first three of these points are listed in your answer choices.

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Step-by-step explanation:

Always include the steps and/or background required to get to the final answer. Let’s help other people understand and solve future problems on their own. Show all the calculation if it is a numerical question.

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