-24a²- 6a +9 = - 3(8a² +6a - 9)
8a² +6a - 9 =0
x=(-b +/-√(b² - 4ac))/2a
x = (-6 +/-√(36+4*8*9) /(2*8) = (-6 +/-√(324) /16 = (-6 +/-18)/16
x1 = (-6 +18)/16 = 0.75
x2 = (-6 -18)/16 = - 1.5
-24a²- 6a +9 = - 3(8a² +6a - 9) = -3(a - 0.75)(a + 1.5)
Answer:
1/2m+25
Step-by-step explanation:
if melody pays 1/2 then sophie pays 1/2 too and then she also spends 25 so you just have to add them together.
Answer:
-3/2
Step-by-step explanation:
(y2 -y1)/(x2-x1)
(-2 + 5)/(0 - 2)
For this problem, it is best to draw a plane showing the positive and negative, in x and y axes.
Since it is given that the coordinates of the epicenter is at (0,0), thus it is at the center of the plane.
In order to find the outside boundary of the earthquake, the center-radius equation can be used as follows:
[(x-h)^2] - [(y-k)^2] = r^2
where, (h,k) is the coordinates of the center, which is (0,0), and r is the radius which is equal to 52.
Substituting these values into the standard center-radius equation,
x^2 - y^2 = 52^2
The answer is,
x^2 - y^2 = 2704
