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3 years ago

What is another name for a business name or manufacture's name

Physics

2 answers:

stich3 [128]3 years ago

8 0

Answer:

brand name, or company

Explanation:

a brand name is the kind of product they are selling. a company is the group of peaple that wok together.

Paha777 [63]3 years ago

5 0

Answer: maker or producer

Explanations:

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When an object with a negative charge is moved from point A to point B through an external electrical field, it gains electrical

Sergio039 [100]

Explanation:

As per the problem,

$\Delta U = (V_{B} - V_{A})(-q) > 0$

When q > 0 then -q is a negative charge . Since, change in potential energy ( $\Delta U$ ) increases.

or, $(V_{A} - V_{B})q$ > 0

or, $V_{A} > V_{B}$

Therefore, both positive and negative charge will move from $V_{A}$ to $V_{B}$ and as $V_{B} < V_{A}$ so both of them move through a negative potential difference.

Thus, we can conclude that the true statements are as follows.

The positively charged object moves through a negative potential difference between A and B (that is, VB - VA < 0).

The negatively charged object moves through a negative potential difference between A and B (that is, VB - VA < 0).

4 0

3 years ago

If the magnitude of a positive charge is tripled, what is the ratio of the original value of the electric field at a point to th

ipn [44]

Answer:

b)1 :3

Explanation:

Lets that

The value of a positive charge = q

As we know that electric filed on a point charge given as

$E=\dfrac{Kq}{r^2}$

Where ,K=Constant

q=Charge ,r=Distance

If the value of the charge gets tripled ,q'= 3 q

Then electric filed E'

$E'=\dfrac{Kq'}{r^2}$

$E'=\dfrac{3Kq}{r^2}$

E' = 3 E

Therefore we can say that

$\dfrac{E}{E'}==\dfrac{1}{3}$

therefore the answer will be --

b)1 :3

3 0

3 years ago

Just about everyone at one time or another has been burned by hot water or steam. This problem compares the heat input to your s

tatyana61 [14]

Answer:

$Q_T=63313.5\ J$

Explanation:

Given:

temperature of skin, $T_s=34^{\circ}C$

initial temperature of steam vapour, $T_v=100^{\circ}C$

latent heat of steam, $L=2256\ J.g^{-1}$

mass of steam, $m=25\ g$

specific heat of water, $c=4190\ J.kg^{-1}.K^{-1}=4.19\ J.g^{-1}.K^{-1}$

final temperature, $T_f=34^{\circ}C$

Assuming that no heat is lost in the surrounding.

We know:

$Q=m.c.\Delta T$

Now the total heat given by the steam to form water at the given conditions:

$Q_T=Q_{Lv}+Q_w$ ..............................(1)

where:

$Q_{Lv}=$ latent heat given out by vapour to form water of 100°C

$Q_w=$ heat given by water of 100°C to come at 34°C.

putting respective values in eq. (1)

$Q_T=m(L+c.\Delta T)$

$Q_T=25(2256+4.19\times 66)$

$Q_T=63313.5\ J$

is the heat transferred to the skin.

4 0

3 years ago

A satellite orbits earth with a mean altitude of 361 km. If the orbit is circular, what are the satellite's time period and spee

Advocard [28]

Answer:

v = 7.69 x 10³ m/s = 7690 m/s

T = 5500 s = 91.67 min = 1.53 h

Explanation:

In order for the satellite to orbit the earth, the force of gravitation on satellite must be equal to the centripetal force acting on it:

$F_{gravitation}= F_{centripetal}\\\\\frac{GM_{s} M_{E}}{r^2} = \frac{M_{s} v^2}{r}\\\\\frac{GM_{E}}{r} = v^2\\\\v = \sqrt{\frac{GM_{E}}{r} } \\\\$

where,

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

Me = Mass of Earth = 5.97 x 10²⁴ kg

r = distance between the center of Earth and Satellite = Radius of Earth + Altitude = 6.371 x 10⁶ m + 0.361 x 10⁶ m = 6.732 x 10⁶ m

v = orbital speed = ?

Therefore,

$v = \sqrt{\frac{(6.67 x 10^{-11}N.m^2/kg^2)(5.97 x 10^{24} kg)}{6.732 x 10^6 m} }\\\\$

v = 7.69 x 10³ m/s

For time period satellite completes one revolution around the earth. It means that the distance covered by satellite is equal to circumference of circle at the given altitude.

So, its orbital speed can be given as:

$v = \frac{Circumference of Circle at Given Altitude}{T}\\\\v = \frac{2\pi r}{T}\\\\$

where,

T = Time Period of Satellite = ?

Therefore,

$T = \frac{2\pi r}{v}\\\\T = \frac{(2\pi )(6.732 x 10^6 m}{7.69 x 10^3 m/s}\\\\$

T = 5500 s = 91.67 min = 1.53 h

7 0

3 years ago

On both sides.

goldenfox [79]

Answer:

please put pic of the questions

3 0

3 years ago