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kherson [118]
3 years ago
10

A sled slides along a horizontal surface on which the coefficient of kinetic friction is 0.25. Its velocity at point A is 8.4 m/

s and at point B is 5.8 m/s . Use the impulse-momentum theorem to find how long the sled takes to travel from A to B.
Physics
1 answer:
Bad White [126]3 years ago
7 0

Answer:

1.06 secs

Explanation:

Initial speed of sled, u = 8.4 m/s

Final speed of sled, v = 5.8 m/s

Coefficient of kinetic friction, μ = 0.25

Using the impulse momentum theory, we know that the impulse applied to the sled is equal to change in momentum of the sled:

FΔt = mv - mu

where m = mass of the object

Δt = time interval

F = force applied

The force applied on the sled is the frictional force, which is given as:

F = -μmg

where g = acceleration due to gravity

Therefore:

-μmgΔt =  mv - mu

-μmgΔt = m(v - u)

-μgΔt = v - u

Making Δt subject of formula:

Δt = (v - u) / -μg

Δt = (5.8 - 8.4) / (-0.25 * 9.8)

Δt = -2.6/ -2.45

Δt = 1.06 secs

It took the sled 1.06 secs to travel from A to B.

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A satellite is circling the moon (radius 1700 km) close to the surface at a speed v. A projectile is launched vertically up from
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Explanation:

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Final. At the furthest point

    Emf = U

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Acceleration is centripetal

       a = v² / r

        r= R_moon

       G m M / R_moon² = m v² / R_mon

        G M / R_moon = v²

We substitute in 1

     ½ G M / R_moon + G M (1 / R_max - 1 / R_moon) = 0

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Answer:

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Explanation:

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We have;

The time to maximum height;

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Where;

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∴ 0 = 30 - 9.81 × t

t = 30/9.81 = 3.06 s

The maximum height can be obtained from;

v² = u² - 2·g·s

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