2,000 kg car moving at 5 m/sec to east collides with 6,000 kg car moving 3 m/sec to west. If cars couple together, what is their
1 answer:
The final velocity is 1 m/s west
Explanation:
The problem can be solved by using the principle of conservation of momentum: in an isolated system, the total momentum of the system must be conserved before and after the collision. So we can write:
where:
is the mass of the first car
is the initial velocity of the first car (we take east as positive direction)
is the mass of the second car
is the initial velocity of the second car
is the final velocity of the two cars together after the collision
Re-arranging the equation and substituting the values, we find:
And since the sign is negative, the direction is to west.
Learn more about momentum here:
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Answer:
The beat frequency when each string is vibrating at its fundamental frequency is 12.6 Hz
Explanation:
Given;
velocity of wave on the string with lower tension, v₁ = 35.2 m/s
the fundamental frequency of the string, F₁ = 258 Hz
<u>velocity of wave on the string with greater tension;</u>
where;
v₁ is the velocity of wave on the string with lower tension
T₁ is tension on the string
μ is mass per unit length
Where;
T₁ lower tension
T₂ greater tension
v₁ velocity of wave in string with lower tension
v₂ velocity of wave in string with greater tension
From the given question;
T₂ = 1.1 T₁
<u>Fundamental frequency of wave on the string with greater tension;</u>
<u /><u />
Beat frequency = F₂ - F₁
= 270.6 - 258
= 12.6 Hz
Therefore, the beat frequency when each string is vibrating at its fundamental frequency is 12.6 Hz