Answer:
Initial velocity, u=15m/s
Initial velocity, u=15m/sFinal velocity, v=0m/s
Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18m
Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18mAcceleration, a=?
Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18mAcceleration, a=?Using relation, v
Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18mAcceleration, a=?Using relation, v 2
Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18mAcceleration, a=?Using relation, v 2 −u
Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18mAcceleration, a=?Using relation, v 2 −u 2
Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18mAcceleration, a=?Using relation, v 2 −u 2 =2as
Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18mAcceleration, a=?Using relation, v 2 −u 2 =2as0
Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18mAcceleration, a=?Using relation, v 2 −u 2 =2as0 2
Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18mAcceleration, a=?Using relation, v 2 −u 2 =2as0 2 −(15)
Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18mAcceleration, a=?Using relation, v 2 −u 2 =2as0 2 −(15) 2
Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18mAcceleration, a=?Using relation, v 2 −u 2 =2as0 2 −(15) 2 =2a×18
Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18mAcceleration, a=?Using relation, v 2 −u 2 =2as0 2 −(15) 2 =2a×18−225=36a
Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18mAcceleration, a=?Using relation, v 2 −u 2 =2as0 2 −(15) 2 =2a×18−225=36aa=
Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18mAcceleration, a=?Using relation, v 2 −u 2 =2as0 2 −(15) 2 =2a×18−225=36aa= 36
Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18mAcceleration, a=?Using relation, v 2 −u 2 =2as0 2 −(15) 2 =2a×18−225=36aa= 36−225
Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18mAcceleration, a=?Using relation, v 2 −u 2 =2as0 2 −(15) 2 =2a×18−225=36aa= 36−225
Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18mAcceleration, a=?Using relation, v 2 −u 2 =2as0 2 −(15) 2 =2a×18−225=36aa= 36−225 =−6.25m/s
Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18mAcceleration, a=?Using relation, v 2 −u 2 =2as0 2 −(15) 2 =2a×18−225=36aa= 36−225 =−6.25m/s 2
Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18mAcceleration, a=?Using relation, v 2 −u 2 =2as0 2 −(15) 2 =2a×18−225=36aa= 36−225 =−6.25m/s 2
Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18mAcceleration, a=?Using relation, v 2 −u 2 =2as0 2 −(15) 2 =2a×18−225=36aa= 36−225 =−6.25m/s 2 So, deceleration is 6.25m/s
Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18mAcceleration, a=?Using relation, v 2 −u 2 =2as0 2 −(15) 2 =2a×18−225=36aa= 36−225 =−6.25m/s 2 So, deceleration is 6.25m/s 2
Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18mAcceleration, a=?Using relation, v 2 −u 2 =2as0 2 −(15) 2 =2a×18−225=36aa= 36−225 =−6.25m/s 2 So, deceleration is 6.25m/s 2 .
