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Stels [109]
3 years ago
8

Please help me with correct answer

Mathematics
1 answer:
BaLLatris [955]3 years ago
4 0
D. -15

All I did was plug the numbers in
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2 years ago
A car is travelling at exactly 6 miles per hour and accelerates at a constant rate to exactly 65 miles per hour.
vichka [17]

Answer:

14878.04878miles/hours^2

Step-by-step explanation:

Let's find a solution by understanding the following:

The acceleration rate is defined as the change of velocity within a time interval, which can be written as:

A=(Vf-Vi)/T where:

A=acceleration rate

Vf=final velocity

Vi=initial velocity

T=time required for passing from Vi to Vf.

Using the problem's data we have:

Vf=65miles/hour

Vi=6miles/hour

T=14.8seconds

Using the acceleration rate equation we have:

A=(65miles/hour - 6miles/hour)/14.8seconds, but look that velocities use 'hours' unit while 'T' uses 'seconds'.

So we need to transform 14.8seconds into Xhours, as follows:

X=(14.8seconds)*(1hours/60minutes)*(1minute/60seconds)

X=0.0041hours

Using X=0.0041hours in the previous equation instead of 14.8seconds we  have:

A=(65miles/hour - 6miles/hour)/0.0041hours

A=(61miles/hour)/0.0041hours

A=(61miles)/(hour*0.0041hours)

A=61miles/0.0041hours^2

A=14878.04878miles/hours^2

In conclusion, the acceleration rate is 14878.04878miles/hours^2

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3 years ago
Kyle charges 50¢ for a cup of lemonade. Kyle can represent the total sales for the day using the expression 50c. Kyle is thinkin
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The perimeter of this figure is 70 feet. How long are the unknown sides?
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3 years ago
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PLS HELP ME, I REALLY NEED THIS RIGHT NOW, 100 POINTS, IF YOU ANSWER WITH NO EXPLANATION, OR ANSWER FOR THE POINTS YOU WILL BE R
Reika [66]

9514 1404 393

Answer:

  • 0 ≤ m ≤ 7
  • 0.4541 cm/month; average rate of growth over last 4 months of study

Step-by-step explanation:

<u>Part A</u>:

The study was concluded after 7 months. The fish cannot be expected to maintain exponential growth for any significant period beyond the observation period. A reasonable domain is ...

  0 ≤ m ≤ 7

__

<u>Part B</u>:

The y-intercept is the value when m=0. It is the length of the fish at the start of the study.

__

<u>Part C</u>:

The average rate of change on the interval [3, 7] is given by ...

  (f(7) -f(3))/(7 -3) = (4(1.08^7) -4(1.08^3))/4 = 1.08^3·(1.08^4 -1)

   ≈ 0.4541 cm/month

This is the average growth rate of the fish in cm per month over the period from 3 months to 7 months.

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