1. The remaing area of the yard will be found as follows:
Area of the yard
A1=length*width=10x*15x=150x^2 yd^2
area of the fountain
A2=πr²
A2=π(4x)²
=50.266x^2
The remaining area will be:
A=150x^2-50.266x^2
A=99.735x^2 yd^2
2] Area left for bleachers, restrooms and other parts of the stadium will be as follows:
Area of the lot is:
A1=length*width
A1=8x×12x= 96x^2
Area of the field
A2=length×width
A2=3x×6x=18x^2
Hence the remaining area will be:
A1-A2
=96x^2-18x^2
=78x^2 sq. units
Answer:
RT = 86
Step-by-step explanation:
Here, we want to find the value of RT
looking at the given triangle, we can deduce that the smaller triangle SPQ is half the measure of the bigger triangle SRT
what this mean is that we have to multiply the dimensions on SPQ by 2 to get the equivalent dimensions of similar sides in SRT
Thus, we have it that;
2(15x -17) = 23x -6
30x - 34 = 23x -6
30x -23x = -6 + 34
7x = 28
x = 28/7
x = 4
So, we make a substitution
for RT;
23x-6
= 23(4) - 6 = 92-6 = 86
Your answer is going to be D.
In order to find P, you would divide $10.25 by 50, which means the 50p is $10.50.
Answer:
A and C
Step-by-step explanation:
For a table of x and y variables to be a function, each x-value must not have two different y-values assigned or related to it. However, different x-values can have the same y-value.
Therefore, the table in option A and option C are functions because every of their x-value has exactly one y-value that corresponds it.
