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2 years ago

PLEASE HELP WITH PAGE 1 FOR QUESTIONS 1, 2, 3 WITH THE GRAPHING THANK YOU.

Chemistry

1 answer:

Scrat [10]2 years ago

6 0

I need a picture in order to answer that question.

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A sample of 28 Mg decays initially at a rate of 53500 disintegrations per minute, but the decay rate falls to 10980 disintegrati

prisoha [69]

Answer : The half life of 28-Mg in hours is, 6.94

Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

$k=\frac{2.303}{t}\log\frac{a}{a-x}$

where,

k = rate constant

t = time passed by the sample = 48.0 hr

a = initial amount of the reactant disintegrate = 53500

a - x = amount left after decay process disintegrate = 53500 - 10980 = 42520

Now put all the given values in above equation, we get

$k=\frac{2.303}{48.0}\log\frac{53500}{42520}$

$k=9.98\times 10^{-2}hr^{-1}$

Now we have to calculate the half-life.

$k=\frac{0.693}{t_{1/2}}$

$9.98\times 10^{-2}=\frac{0.693}{t_{1/2}}$

$t_{1/2}=6.94hr$

Therefore, the half life of 28-Mg in hours is, 6.94

8 0

2 years ago

1. Define flash flood.

BigorU [14]

A flash flood is when to much water overflows a certain area. This is common with storms. When it rains; small bridges tend to floor. Garages, basements, and cellars can tend to flood as well from storms.

7 0

2 years ago

Read 2 more answers

Does anyone know Bible thing cuz I don’t know what to write and I need help if you know this ok

Keith_Richards [23]

I answered all of them except 2 for you to do

Hope this helps :))

Download docx

4 0

2 years ago

Can someone help me with this molar mass problem?[It’s the last one]

quester [9]

Answer:

$54.18 \times 10^{23} \ moles$ in 3 mole of $Al_2(SO_4)_3$

Explanation:

It is clear that in the given $1\ mole$ of $Al_2(SO_4)_3$ have $3\ ions$ of $SO_4^2^-$

Therefore 3 moles of $Al_2(SO_4)_3$ will have $3\times3=9 \ ions$ of $SO_4^2^-$

Since 1 ion of anything is equivalent to $6.02\times10^{23} \ moles$

Therefore 3 moles of $Al_2(SO_4)_3$ will have $3\times3=9 \ ions$ of $SO_4^2^-$

Which is equivalent to $9 \times6.02\times10^{23}=54.18\times10^{23} \ moles$

Thus 3 moles of $Al_2(SO_4)_3$ gives $54.18\times10^{23} \ moles$ of $SO_4^2^-$ .

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3 years ago

A common misconception people have is that sugar is energy and energy is sugar but you know better. Create a clear explanation t

Gnom [1K]

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2 years ago