When the name of ions end with ide, is it true that they are all negative ions

What net ionic equation describes the reaction between Pb(NO3)2(aq) and Na2CO3(aq)?

loris [4]

Answer:

Pb⁺²(aq) + CO₃⁻²(aq) → PbCO₃ (s)

In net ionic equation we cancel the ions that have equal moles on both sides so Na⁺¹ and NO₃⁻¹ have equal moles on both sides so we canceled them.

Explanation:

Net ionic equation:

In net ionic equation we only write the ions that are involved in reaction. If the system have same moles of ions in initial and final stages we cancel them as they have the same amount and are present in ionic form in the reaction medium. To formulate an ionic equation we just cancel the ions which have the same moles in initial and final stages.

Chemical equation:

Pb(NO₃)₂ (aq) + Na₂CO₃(aq) → PbCO₃ (s) + NaNO₃ (aq)

Balanced chemical equation:

In a balanced chemical equation we write the reactants and products in molecular form with number of moles.

Pb(NO₃)₂ (aq) + Na₂CO₃(aq) → PbCO₃ (s) + 2NaNO₃ (aq)

Ionic equation:

In ionic equation we write the equation in ionic form. It involves all the ions which will produce when we add any ionic compound in reaction medium.

Pb⁺² +2NO₃⁻¹ + CO₃⁻² + 2Na⁺¹ → PbCO3 (s) + 2NO₃⁻¹ (aq) + 2Na⁺¹ (aq)

Net ionic equation

In net ionic equation we cancel the ions that have equal moles on both sides. As we can see in the above ionic equation that Na⁺¹ and NO₃⁻¹ have equal moles on both sides so we canceled them.

Pb⁺²(aq) + CO₃⁻²(aq) → PbCO₃ (s)

7 0

4 years ago

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Arrange the following substances in order of increasing solubility of water. C6H14, C6H13Br, C6H13OH, C6H12(OH)2.

Juli2301 [7.4K]

Answer:

C6H14 < C6H13Br < C6H13OH < C6H12(OH)2

Explanation:

Hello,

In this case, since the solubility in water is related with the presence of polar bonds in the given molecules we can see that C6H12(OH)2 has the presence two O-H bonds which promote the highest solubility via hydrogen bonds as well as the C6H13OH but in a lower degree as only on O-H bond is present. Next since the bond C-Br in is slightly close to the polar bond C6H13Br rather than the C-C bonds only had by C6H14 we can infer that C6H13Br is more soluble in water than C6H14, therefore the required order is:

C6H14 < C6H13Br < C6H13OH < C6H12(OH)2

Whereas C6H12(OH)2 is the most soluble and C6H14 the least soluble in water.

Best regards.

5 0

3 years ago

3. 53.2 g C reacts with Iron (III) oxide, how many grams of iron can be produced?

Vikentia [17]

Answer:

a

Explanation:

a

8 0

3 years ago

The equation below shows the relationship between the temperature in degrees Celsius, C, and degrees Fahrenheit, F.

anyanavicka [17]

The initial equation is <span>F = (9/5)C + 32. We are asked to get the formula to solve for C. So the idea here is to isolate C on the other side, where F is currently located.

1. Subtract 32 on both sides.
2. Divide 9/5 on both sides.

You should get </span><span>C = 5 over 9(F – 32) as your answer. </span>

3 0

4 years ago

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The boiling point of ethanol (C₂H₅OH) is 78.5°C. What is the boiling point of a solution of 6.4 g of vanillin M = 152.14 g/mol)

Gwar [14]

The boiling point of a solution of 6.4 g of vanillin in 50.0g of ethanol is 77.47 degree C.

Change in boiling point of solution

ΔTb = (Kb)(m), where

ΔTb = change in temperature

Kb = elevation constant = 1.22 °C./m

m = molality of the solution

Following the calculation of the moles of vanillin, the molality of vanillin in ethanol will be determined..

Moles of vanillin = 6.4g / 152.12g/mol = 0.042 mol

m of vanillin = 0.042mol / 0.05kg = 0.84m

putting all values on the above equation,

ΔTb = (1.22)(0.84) = 1.0248 °C.

Given;

boiling point of ethanol = 78.5 °C.

So the boiling point of vanillin = 78.5 - 1.0248 = 77.47 °C

Hence, the boiling point of a solution of vanillin is 77.47 °C.

Learn more about the boiling point with the help of the given link:

brainly.com/question/1514229

#SPJ4

6 0

2 years ago