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Aleonysh [2.5K]
3 years ago
5

In your own words, give two reasons why it is important to work with a partner while completing a lab.

Chemistry
1 answer:
kap26 [50]3 years ago
6 0
In order to collaborate to come up with ideas, and to ensure that the other person is being safe. Diversity among groups/teams create more diverse and complete answers.
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Ocean water contains 3.5 nacl by mass. what mass of ocean water in grams contains 45.8 g of nacl
Romashka-Z-Leto [24]

Mass percentage of sodium chloride(NaCl) in ocean waters = 3.5 %

That means 3.5 g sodium chloride(NaCl) is present for every 100 g of ocean water.

The given mass of sodium chloride(NaCl) is 45.8 g

Calculating the mass of ocean waters that would contain 45.8 g sodium chloride(NaCl):

45.8 g NaCl *\frac{100g ocean water}{3.5g NaCl}

                     = 1309 g ocean water

Therefore, 45.8 g sodium chloride is present in 1309 g ocean water.

3 0
3 years ago
Given the standard entropy values in the table, what is the value of º for the following reaction?
Mandarinka [93]
Hello.

The answer is <span>+313.766 J/mol·K
</span>
 Use the coefficients of the reaction and sum the product entropies less the reactant entropies:

4*188.8 + 2*213.7 - 3*205.1 - 2* 126.8 = 313.7 J/mol*K

Have a nice day
8 0
3 years ago
Electroplating is a way to coat a complex metal object with a very thin (and hence inexpensive) layer of a precious metal, such
8_murik_8 [283]

Answer:

0.0164 g

Explanation:

Let's consider the reduction of silver (I) to silver that occurs in the cathode during the electroplating.

Ag⁺(aq) + 1 e⁻ → Ag(s)

We can establish the following relations.

  • 1 A = 1 C/s
  • The charge of 1 mole of electrons is 96,468 C (Faraday's constant)
  • 1 mole of Ag(s) is deposited when 1 mole of electrons circulate.
  • The molar mass of silver is 107.87 g/mol

The mass of silver deposited when a current of 0.770 A circulates during 19.0 seconds is:

19.0s \times \frac{0.770c}{s} \times \frac{1mole^{-} }{96,468C} \times \frac{1molAg}{1mole^{-}} \times \frac{107.87g}{1molAg} = 0.0164 g

5 0
3 years ago
How many grams of oxygen would be needed to completely react with 18 grams of methane (CH4)?
S_A_V [24]

Answer:

35.91 grams of oxygen

Explanation:

6 0
3 years ago
Which statement is true about magnetic poles
Ahat [919]
A. all magnets have two poles

5 0
3 years ago
Read 2 more answers
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