Answer: the smallest is 2^5, 6^2, 3^4 and the largest is 5^3
Answer:

Step-by-step explanation:
Let suppose that airliners travel at constant speed. The equations for travelled distance of each airplane with respect to origin are respectively:
First airplane

Where t is the time measured in hours.
Since north and west are perpendicular to each other, the staight distance between airliners can modelled by means of the Pythagorean Theorem:

Rate of change of such distance can be found by the deriving the expression in terms of time:

Where
and
, respectively. Distances of each airliner at 2:30 PM are:


The rate of change is:


Answer:
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Answer:
Quarters: 10
Dimes: 8
Step-by-step explanation:
Constraints
value: 0.25q + 0.10d = 3.30
count: q + d = 18
q = 18 - d
0.25(18-d) + 0.10d = 3.30
4.50-0.25d+0.10d = 3.30
4.50-0.15d = 3.30
-0.15d = -1.20
d = 8
q + d = 18
q + 8 = 18
q = 10
Check:
0.25(10) + 0.10(8) = 3.30
2.5+ 0.80 = 3.30
3.30 = 3.30