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Nady [450]
3 years ago
13

3. Give the slope and y-intercept of the relationship shown in the table.

Mathematics
1 answer:
kolezko [41]3 years ago
4 0

Answer:

B

Step-by-step explanation:

Since the slope is going down the slope is negative and since 50 is positive when 0 its positive.

Also to find slope you do y/x

25/100=1/4 and since its a decreasing pattern the slope is -1/4

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Katen [24]
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3 years ago
• Trey attended a New Year's Eve event and watched a ball drop at midnight. Prior
jekas [21]

Answer:

x=60.9°

Step-by-step explanation:

Given that the height of ball from the ground is 150ft

The base of the pole with the ball is 80 ft from where Trey is standing

Trey's horizontal line of sight is 6 feet above ground, then;

The height of ball from Trey's horizontal line of sight is;

150ft-6ft = 144ft

To find the angle x, assume a triangle with a base of 80 ft , a height of 144 ft and a slant height that represent the line of sight at an angle x

To get angle x , you apply the tangent of an angle formula where;

tan Ф°= length of opposite site of the angle/length of the adjacent side of the angle

tan x°= 144/80

tan x°=  1.8

x°= tan⁻(1.8)

x°=60.9°

7 0
3 years ago
Find the area of the composite shape below<br> help me
Ivenika [448]

Answer:

743.13

Step-by-step explanation:

area of the rectangle is 33x11 which is 363 and there are two equal half circles so we can just pretend they are connected so the radius is 11 A=pi times radius^{2} which is 380.13 then add both of them and you get 743.13

8 0
2 years ago
Which wave would have the higher pitch? Question 7 options: B A
Arte-miy333 [17]
A. would have the highest pitch because the sound vibration are close together and it would also be the fastest. B is incorrect because the sound waves are very which would give it a deeper voice and it would be the slowest 

Hope this helps
8 0
3 years ago
The greatest common factor of 3m^2n+12mn^2 is
FromTheMoon [43]
3m^2n=3mn\cdot m\\\\12mn^2=3mn\cdot4n\\\\GCF(3m^2n;\ 12mn^2)=3mn\\\\3m^2n+12mn^2=3mn(m+4n)
6 0
3 years ago
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