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3 years ago

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3. Give the slope and y-intercept of the relationship shown in the table.

1 answer:

kolezko [41]3 years ago

4 0

Answer:

B

Step-by-step explanation:

Since the slope is going down the slope is negative and since 50 is positive when 0 its positive.

Also to find slope you do y/x

25/100=1/4 and since its a decreasing pattern the slope is -1/4

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Make your own word problem using 2 equivalent RATES.

andre [41]

At the store, 3 apples cost 12 dollars. how much money will it cost for 6 apples?

4 0

3 years ago

The slope of the line below is -2. Use the coordinates of the labeled point to

Vilka [71]

Answer:

We can express the equation for any linear equation with slope -2 and point (x0,y0) as:

$y=-2x+(y_0+2x_0)\\\\y-y_0=-2(x-x_0)$

Step-by-step explanation:

Incomplete question:

There is no point to complete the equation.

As we have no point to complete the linear equation, we will solve for any given point (x0,y0) and a slope of m=-2.

The linear equation can be written generically as:

$y(x)=mx+b\\\\y(x)=-2x+b$

If a point, like (x0,y0) belongs to the linear equation, it satisfies its equation. Then:

$y_0=-2x_0+b$

Then, we can calculate b as:

$y_0=-2x_0+b\\\\b=y_0+2x_0$

We can express the equation for any linear equation with slope -2 and point (x0,y0) as:

$y=-2x+(y_0+2x_0)\\\\y-y_0=-2(x-x_0)$

6 0

3 years ago

Is x 12 or 15? Or none?

Usimov [2.4K]

The answer is 15 buddy!

7 0

3 years ago

Read 2 more answers

HELPPP!! ASAP PLZ!!!

ExtremeBDS [4]

Answer:

J: 84%.

Step-by-step explanation:

I don't really know how to explain this one.

8 0

3 years ago

Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

4 0

3 years ago