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Rudiy27
3 years ago
14

What is the square root of r64?

Mathematics
2 answers:
motikmotik3 years ago
7 0

Answer:

The answer is B (r8)

Step-by-step explanation:

IceJOKER [234]3 years ago
4 0

Answer:8

Step-by-step explanation:

Simplify the radical.

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5 girls to 2 boys, it’s not asking for boys and girls
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Please help me figure this out
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I believe the answer is B
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Help me guys <br> thx so much
navik [9.2K]

Answer:

Option D, 10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

Step-by-step explanation:

<u>Step 1:  Multiply</u>

<u />(\sqrt{10x^4} -x\sqrt{5x^2} )*(2\sqrt{15x^4} + \sqrt{3x^3})\\ (\sqrt{10 * x^2 * x^2} -x\sqrt{5 * x^2} ) * (2\sqrt{15 * x^2 * x^2} +\sqrt{3 * x^2 * x})\\(x^2\sqrt{10} -x^2\sqrt{5} )*(2x^2\sqrt{15} +x\sqrt{3x}) \\\\

(x^2\sqrt{10}*2x^2\sqrt{15} )+(x^2\sqrt{10}*x\sqrt{3x} ) + (-x^2\sqrt{5} *2x^2\sqrt{15}) + (-x^2\sqrt{5} *x\sqrt{3x}

(2x^4\sqrt{150} ) + (x^3\sqrt{30x}) + (-2x^4\sqrt{75}) + (-x^3\sqrt{15x}  )

2x^4\sqrt{5^2*6} + x^3\sqrt{30x} -2x^4\sqrt{5^2*3} -x^3\sqrt{15x}

10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

Answer:  Option D, 10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

6 0
3 years ago
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Answer:

17.7

Step-by-step explanation:

<em>First off, we do not need to do anything to the 17, it is already set up for a decimal. So we have to find out how much 1/50 is so we divide:</em>

<u>Divide:</u>

1/50=0.02

<u>Multiply by 35:</u>

0.02 times 35= 0.7

<u>Add the 17:</u>

17+0.7=<em><u>17.7</u></em>

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What is 6(m + 4) =_m +_
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