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jasenka [17]
2 years ago
15

I have another challenge!

Mathematics
2 answers:
Anna [14]2 years ago
6 0
3rd option as it just is
guapka [62]2 years ago
5 0

Answer:

3rd option, the (3*5)*37=x

Step-by-step explanation:

3 times per day, multiplied by 5 days, you get the total for those five days. then multiply that total by the amount of weeks, getting that.

correct me if it is wrong though.

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What is the force of a 12 kg object that is accelerating at a rate of 6 m/s2?
Leviafan [203]

Answer:

force= mass × acceleration

12×6

72 N

7 0
3 years ago
Javine says, "To multiply by 1000, I just add three zeros." Kian says, "I times by 10, then times by 10 and times by 10 again."
aksik [14]

Answer:

Kian's method is correct.

Step-by-step explanation:

Javine says, "To multiply by 1000, I just add three zeros." He is incorrect.

Kian says, "I times by 10, then times by 10 and times by 10 again. When he multiply 1 by 10, it becomes 10. Then if he again multiply by 10, it becomes 10×10 = 100. And at last when he multiply again 10, it becomes 100×10 = 1000. It means Kian's methods for multiplying by 1000 is correct.

8 0
2 years ago
What is the mean set of numbers -3, -2,0,3,17
Elan Coil [88]

I think its 2

Just give me a like

6 0
3 years ago
Read 2 more answers
I hope this uploaded sorry still having a hard time with this one
Shkiper50 [21]
No problem 72 cubic squares
8 0
3 years ago
A certain three​-cylinder combination lock has 60 numbers on it. To open​ it, you turn to a number on the first​ cylinder, then
statuscvo [17]

Answer:

(a) The number of different lock combinations is 216,000.

(b) The probability of getting the correct combination in the first try is \frac{1}{216000}.

Step-by-step explanation:

The lock has three-cylinder combinations with 60 numbers on each cylinder.

The procedure of the opening lock is to turn to a number on the first​ cylinder, then to a second number on the second​ cylinder, and then to a third number on the third cylinder.

The numbers can be repeated.

(a)

There are three cylinder combinations on the lock, each with 60 numbers.

It is provided that repetitions are allowed.

Then each cylinder can take any of the 60 numbers.

So there are 60 options for the first cylinder.

There are 60 options for the second cylinder.

And there are 60 options for the third cylinder.

So the total number of possible combinations is:

Total number of combinations = 60 × 60 × 60 = 216000.

Thus, the number of different lock combinations is 216,000.

(b)

The events of getting a correct combinations of the three​-cylinder combination lock implies that all the three cylinder are set at the correct numbers.

Each cylinder has 60 numbers.

This implies that there are 60 possible ways to get a correct number for the first cylinder.

The probability of getting the correct number for the first cylinder is:

P (Number on 1st cylinder is correct) = \frac{1}{60}.

Similarly for the second cylinder the probability of getting the correct number is:

P (Number on 2nd cylinder is correct) = \frac{1}{60}.

And similarly for the third cylinder the probability of getting the correct number is:

P (Number on 3rd cylinder is correct) = \frac{1}{60}.

So the probability of getting the correct combination in the first try is:

P (Correct combination in the 1st try) = \frac{1}{60}\times \frac{1}{60}\times \frac{1}{60}=\frac{1}{216000}.

Thus, the probability of getting the correct combination in the first try is \frac{1}{216000}.

7 0
3 years ago
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