1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SVETLANKA909090 [29]
3 years ago
6

84 times 0.24 area model

Mathematics
2 answers:
Paraphin [41]3 years ago
7 0
Can you explain more please i am willing to help but your question doesnt really have anything to do.
CaHeK987 [17]3 years ago
4 0
I'm not sure if I get what you mean, because I don't think I remeber what an area model is. But if it literally means making a model to describe the area, you could draw a square and put 84 on the length or the width and the o.24 on the other. Show that length times width = area. And then multiply. But if I am right, that's not what you are looking for, huh?
You might be interested in
Plsss. Help plalssssssa
pshichka [43]
We cannot see the whole question
3 0
3 years ago
Hii! Can anyone please help me with this? I'm giving 30 points and BRAINLIEST!! TYSM. :D
jeyben [28]

Answer:

I added a picture, with the answers. I hope it’s good.

Step-by-step explanation:

3 0
3 years ago
For the matrices below. Find all (real) eigenvalues. <br><br> A= [7 9]<br> [0 9]
Jet001 [13]

Answer:

The answer is "9 and 7".

Step-by-step explanation:

Given:

A=\left[\begin{array}{cc}7&9\\0&9\end{array}\right]

Using formula:

|A-\lambda \cdot I|= 0\\\\

\to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]-\lambda \left[\begin{array}{cc}1&0\\0&1\end{array}\right] |=0\\\\\\ \to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]- \left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right] |=0\\\\\\\to|\left[\begin{array}{cc}7-\lambda &9\\0&9-\lambda\end{array}\right]|=0\\\\\\\to|(7-\lambda)(9-\lambda)|=0\\\\\to (7-\lambda)(9-\lambda)=0\\\\\to 7-\lambda=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 9-\lambda=0\\\\

\to \lambda=7 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \lambda=9\\\\

8 0
3 years ago
Violet was carrying around the steps to solve Square root of 3x plus 1 =
Artyom0805 [142]
\sqrt{3x+1} = 4
First, square both sides (d.) leaving 3x + 1 = 16
Second, subtract 1 from both sides (a.) leaving 3x = 15
Third, divide by 3 from both sides (e.) leaving x = 5
Answer: First D, then A, then E

7 0
3 years ago
The length of the rectangular table is 5 inches longer than the width. the perimeter is at least 92 inches.which range shows the
alexandr402 [8]
The perimeter is 
P = 2w + 2l
the rectangular table is 5 inches longer than the width
P = 2w + 2(w + 5)

now we can use that to solve
P = 2w + 2w + 10
P = 4w + 10

P > 92
10 + 4w > 92
subtract 10 from both sides
4w > 82
Divide both sides by 4
w > 20.5

The width can be greater than or equal to 20.50 inches.

Hope this helps :)

8 0
2 years ago
Read 2 more answers
Other questions:
  • How many zeros does this polynomial function, y=(x-8)(x+3)^2
    11·2 answers
  • Foil pattern (7k+8)(5k+6)
    7·1 answer
  • A researcher in environmental science is conducting a study to investigate the impact of a particular herbicide on fish. He has
    10·1 answer
  • 5 thousands 2 hundreds 4 ones + 3 thousands 7 hundreds 5 ones in standard form
    8·1 answer
  • For the following systems of equations, match each diagram on the left with its solution on the right.
    15·2 answers
  • 1. Six more than the number of pumpkins tripled
    12·1 answer
  • Mariam's uncle donates 120 cans of juice and 88 packs of cheese crackers for a school picnic each student must receive the same
    6·2 answers
  • There are 300 men and women at an afterschool meeting. 3/5 of the people are women. How many women are at the meeting? How many
    13·2 answers
  • Susan has 48 coins totalling $8.00 and the coins are all nickels and quarters. Which system of equations can be used to determin
    7·1 answer
  • 4(x)+2 Is -18 what is x
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!