All categories

3 years ago

Solve -Q=1/2p+15,for p

Mathematics

2 answers:

alukav5142 [94]3 years ago

4 0

P=-2Q-30 is the answer

3241004551 [841]3 years ago

4 0

Hello there!

-q = 1/2p + 15
Solve for P
-2pq = 30p + 1
-2pq - 30p= 1
Factor out the variable P
p(-2q - 30)=1
Now we can divide both sides by -2q-30
p(-2q - 30)/-2q - 30 = 1/-2q - 30
P = -1/(2q+30)

I hope I helped!

You might be interested in

There are 20 sweets in a box.

natima [27]

Answer:

$probability \: of \: getting \: red \: sweets = \frac{x}{20} \\ probability \: of \: getting \: yellow \: sweets \: = \frac{(20 - x)}{20}$

5 0

3 years ago

Miguel e nádia trabalham num escritório de contabilidade. A cada 45 minutos miguel vai á sala de café para relaxar um pouco, enq

Kazeer [188]

Responder:

3 horas

Explicação passo a passo:

Dado :

Miguel a cada 45 minutos

Nádia a cada 60 minutos

Número de horas que eles vão se ver no mesmo lugar:

Para fazer isso ;

Obtenha o menor múltiplo comum de 60 e 45

Múltiplos de:

45: 45, 90, 135, 180, 225.

60: 60, 120, 180, 240, 300.

O menor múltiplo comum de 45 e 60 é 180

° Assim, eles se verão no mesmo lugar após 180 minutos;

Número de horas = 180/60 = 3 horas

6 0

2 years ago

Plot the corresponding points for the inverse of the function represented by this table of values. x -4 0 3 7

NNADVOKAT [17]

Answer:

See explanation

Step-by-step explanation:

Given the function f(x) for which

$\begin{array}{ccccc}x&-4&0&3&7\\ \\f(x)&9&5&2&-2\end {array}$

If you want to plot the corresponding points for the inverse of the function f(x), change $f(x)$ into $y$ :

$\begin{array}{ccccc}x&-4&0&3&7\\ \\y&9&5&2&-2\end {array}$

switch x and y

$\begin{array}{ccccc}y&-4&0&3&7\\ \\x&9&5&2&-2\end {array}$

and then change $y$ into $f^{-1}(x).$

You get

$\begin{array}{ccccc}x&9&5&2&-2\\ \\f^{-1}(x)&-4&0&3&7\end {array}$

Now plot these points on the coordinate plane (see attached diagram).

3 0

3 years ago

Which function best models the data in the graph?

Alex777 [14]

I g=2.04x
O y=10.2/x

8 0

3 years ago

Read 2 more answers

Two congruent 30-60-90 triangles are placed,as shown,so that they overlap partly and their hypotenuses coincide. If the hypotenu

Ede4ka [16]

Answer: The area common to both triangle is 31.77 sq. cm.

Step-by-step explanation:

Since we have given that

30-60-90 triangles are placed.

So, the ratio of sides would be

$1:\sqrt{3}:2$

Since Hypotenuse = 12 cm

So, it becomes,

$2x=12\\\\x=\dfrac{12}{2}=6$

So, Base would be

$x=6\ cm$

and Perpendicular would be

$\sqrt{3}x=6\sqrt{3}$

So, Area common to the both triangles would be

$\dfrac{1}{2}\times base\times height\\\\=\dfrac{1}{2}\times 6\times 6\sqrt{3}\\\\=18\sqrt{3}\\\\=31.177$

Hence, the area common to both triangle is 31.77 sq. cm.

4 0

3 years ago