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jek_recluse [69]

3 years ago

8

after typing 1/4 of a term paper on Friday, Richard completed 2/3 of the remainder on Saturday. If he wanted to finish the paper

that weekend, what part was left to be typed on Sunday?

1 answer:

boyakko [2]3 years ago

5 0

Hope you can read my handwriting.

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a ramp measures 6 feet long. if the ramp is 12 inches tall, what is the horizontal distance that it covers?

svp [43]

We know that

1 ft--------> is equals to 12 in
the ramp is 12 inches tall----------> 1 ft tall
<span>A ramp measures------------------> 6 ft long
</span>
<span>applying the Pythagorean theorem
</span>c²=a²+b²
where
c-----> 6 ft long
a----> horizontal distance
b-----> 1 ft tall

a²=c²-b²------> a²=6²-1²-----> a²=35------> a=√35------> a=5.92 ft

the answer is
5.92 ft

8 0

3 years ago

PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi

Irina18 [472]

Answer:

Question 1: $P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}$

Question 2:

A. $P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

B. $P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

C. $P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

Step-by-step explanation:

Conditional probability is defined by

$P(A|B)= \frac{P(A and B)}{P(B)}$

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} } = \frac{1}{2}$

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

$P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

then

$P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

so

$P((YorZ) and B)= \frac{3}{16}$

By definition,

$P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

3 0

3 years ago

At what values of x does the graph of f(x)= sin x intersect the x-axis?

aalyn [17]

D) not fully sure thoe

8 0

3 years ago

Read 2 more answers

What is the greatest common facter of 48 and 84

Snowcat [4.5K]

Answer:12

Step-by-step explanation:

The prime factorization of 84 is 2×2×3×7 . The prime factorization of 48 is 2×2×2×2×3 . . Therefore, the GCF is 2×2×3=12

8 0

3 years ago

Pls help extra points and mark brainlist

juin [17]

Answer:

it is c none of the above

Step-by-step explanation:

4 0

3 years ago