Oxidation numbers play an important role in the systematic nomenclature of chemical compounds. By definition, the oxidation number of an atom is the charge that atom would have if the compound was composed of ions. The oxidation number of simple ions is equal to the charge on the ion. The oxidation number of sodium in the Na+<span> ion is +1.</span>
Explanation:
It is known that the maximum value of ml is equal to the vale of l. But the minimum value of n is as follows.
n = l + 1
where, n = principle quantum number
l = azimuthal quantum number
Values of n can be 1, 2, 3, 4 and so on. Whereas the values of l is 0 for s, 1 for p, 2 for d, 3 for f, and so on.
Also, "m" is known as magnetic quantum number whose values can be equal to -l and +l.
- Electronic configuration of Li is
. So here, n = 2, l = 0, m = 0 and s = ± 
.
- Electronic configuration of
is ![[Ar]3d^{10}4s^{2}4p^{6} ](https://tex.z-dn.net/?f=%5BAr%5D3d%5E%7B10%7D4s%5E%7B2%7D4p%5E%7B6%7D%0A)
. So here, n = 4, l = 1, m = -1, 0, +1, and s = ± .
- Electronic configuration of
is ![[Kr]4d^{10}5s^{2}5p^{6}](https://tex.z-dn.net/?f=%5BKr%5D4d%5E%7B10%7D5s%5E%7B2%7D5p%5E%7B6%7D)
. So here, n = 5, l = 1, m = -1, 0, +1, and s = ± .
- Electronic configuration of B is
. So here, n = 2, l = 1, m = -1, 0, +1, and s = ± .
Answer:
Explanation:
Alkali metals ------ outermost orbit containing one electron
ns²np¹
Alkaline metals -------- outermost orbit containing two electron
ns²np²
halogens --------------- outermost orbit containing seven electron
ns²np⁵
noble gas --------------- outermost orbit containing eight electron
ns²np⁶.
Answer: 1.15L
Explanation:Please see attachment for explanation
<span>When electrons are excited they get more energy and jump to higher orbitals. As they loose that energy that had excited them in the beginning, they tend to return to their original orbitals and the color that is given off is when this is occurring. </span>
