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denis23 [38]
3 years ago
5

The colourless coating on a photographic film contains a chemical substance which reacts upon exposure to light, causing the fil

m to darken. Which of the following substances is present in the darkened parts of the film?
A. Bromine

C. Silver

B. Carbon

D. Silver bromide​
Chemistry
1 answer:
zmey [24]3 years ago
5 0

Answer:

D. Silver bromide​

Explanation:

Silver bromide (AgBr) is used in photographic films because silver bromide is light sensitive.

Silver bromide (AgBr) is a colorless coating on a photographic film that decomposes and converted to elemental silver when exposed to the light and causes the film to darken.

Hence, the correct answer is "D. Silver bromide​".

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Draw the structure(s) of all of the possible monochloro derivatives of 2,4-dimethylpentane, c7h15cl.
pishuonlain [190]

The monochloroderivatives will be obtained by substituting chemically non equivalent hydrogen with chlorine atom, one by one

So the possible monochloro derivatives of 2,4-dimethylpentane (figure 1) are shown in figure (2)




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3 years ago
[HELP PLEASE] Describe the difference between the ways valence electrons are rearranged when forming ionic bonds and covalent bo
nydimaria [60]

Answer:

Ionic bonding is the complete transfer of valence electron(s) between atoms. It is a type of chemical bond that generates two oppositely charged ions. In ionic bonds, the metal loses electrons to become a positively charged cation, whereas the nonmetal accepts those electrons to become a negatively charged anion.

Explanation:

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2 years ago
When electrons are filling energy levels, the lowest energy sublevels are occupied first. This is ____________.
Nimfa-mama [501]

When electrons are filling energy levels, the lowest energy sublevels are occupied first. This is Hund's rule.

Hund's rules state that:

Every orbital in a sublevel has to be singularly occupied before any other orbital is able to be doubly occupied.

All of the electrons in single occupied orbitals have to have the same spin to maximize the total spin.

4 0
3 years ago
Read 2 more answers
Thinking and questioning is the start of the scientific inquiry process. Please select the best answer from the choices provided
aev [14]
Yes thats true! You always have to think about the question or project before you start a science experiment! :) 




8 0
3 years ago
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What is the pH of a KOH solution that has [H ] = 1. 87 × 10–13 M? What is the pOH of a KOH solution that has [OH− ] = 5. 81 × 10
vlada-n [284]

pH is the hydrogen ion concentration and pOH is the hydroxide ion concentration in the solution. pH KOH is 12.73, pOH KOH is 2.24 and pH NaCl is 7.

<h3>What are pH and pOH?</h3>

pH is the negative log of the hydrogen ion concentration and pOH is the negative log of the hydroxide ion concentration.

The relation between the pH and pOH can be given as, \rm pOH = 14 - pH

The pH of KOH can be calculated by the formula,

\rm pH = \rm -log [H^{+}]

In the first case, the concentration of the KOH is 1. 87 \times  10^{-13}\;\rm  M

Substituting values in the equation:

\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 87 \times  10^{-13}\;\rm  M ]\\\\&= 12.73\end{aligned}

Hence, the pH of KOH is 12.73.

<u />

pOH of KOH can be calculated by the formula,

\rm pOH = \rm -log [OH^{-}]

The hydroxide concentration of the KOH solution is 5. 81 \times 10^{-3}\;\rm  M

Substituting value in the equation:

\begin{aligned} \rm pOH &= \rm -log [OH^{-}]\\\\&= \rm -log [5. 81 \times 10^{-3}\;\rm  M ]\\\\&= 2.24 \end{aligned}

Hence, the pOH of KOH is 2.24

<u />

The pH of NaCl can be calculated by the formula,

\rm pH = \rm -log [H^{+}]

In the third case, the concentration of the NaCl is 1. 00\times 10^{-7}\;\rm  M

Substituting values in the equation:

\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 00 \times  10^{-7}\;\rm  M ]\\\\&= 7 \end{aligned}

Hence, the pH of KOH is 7.0.

Therefore, KOH is basic and NaCl is approximately neutral.

Learn more about pH and pOH here:

brainly.com/question/13885794

3 0
2 years ago
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