Answer:
How does a dichotomous key help you identify unknown specimens based on their traits?
Explanation:
see pic for edg
D) #recombinant=116+601+4+2+113+625=1462
#nonrecombinant=2538+2708=5246
RF=R/(N+R)=1462/6708=0.2
E) I=1-Q
I-interference
Q-coefficient of coincidence
Q=O2Xo/E2xo(2xo-double crossovers)
O2xo=6
P=(distance from C1 to Sh/100)*(distance from Sh to Wx/100)
=(3.38/100)*(18.28/100)=0.006
E2xo=0.006*6708=40.248
Q=6/40.248=0.15
I=1-0.15=0.85
The condition of the atmosphere at a particular time and place is 'weather'. The answer to the question posted above is 'weather'. Weather is the state of the atmosphere at a given time and place with variables such as wind, temperature and more that affect it.
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(sry have to make an answer 20 characters /!:!27837)