Can someone please help me?

Mathematics

2 answers:

elixir [45]2 years ago

7 0

The answer is -2. -2 is the slope.

lorasvet [3.4K]2 years ago

3 0

The slope is -2/5.

I picked 2 points on the graph and found the slope using the slope formula.

y₂ - y₁ -4 - (-2) -4 + 2 -2
------------ = -------------- = ------------ = ------
x₂ - x₁ 5 - 0 5 5

You can also find slope by using rise/run:
1). Pick 2 points on a graph.
2). The goal is to connect those two points.
3). Count a certain amount of units up and across to get to your second point.
4). If your second point is negative, you have to count a certain amount of units down and across to reach your second point.

If my words don't make any sense, check out www.algebra-class.com. There is a full explanation of this.

I hope I could help you!

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Which answer best describes the complex zeros of the polynomial function?

marysya [2.9K]

Answer-

D. The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location.

Solution-

The given polynomial is,

$f(x)=x^3-x^2+6x-6$

The zeros of the polynomials are,

$\Rightarrow f(x)=0$

$\Rightarrow x^3-x^2+6x-6=0$

$\Rightarrow x^2(x-1)+6(x-1)=0$

$\Rightarrow (x^2+6)(x-1)=0$

$\Rightarrow (x^2+6)=0,(x-1)=0$

$\Rightarrow x=\sqrt{-6},\ x=1$

$\Rightarrow x=1,\ \pm \sqrt6i$

Therefore, this function has only one real zero i.e 1 and two nonreal zeros i.e ±√6i . The graph of the function intersects the x-axis at exactly one location i.e at x = 1