Ask question

Ask question

All categories

IgorLugansk [536]

2 years ago

5

Which of the following is not a type of propaganda?

1 answer:

s344n2d4d5 [400]2 years ago

5 0

Answer:

where are the types of propaganda

You might be interested in

Solve for in the diagram below.

ch4aika [34]

X is 35. 180=75+3x. 180-75/3=35

8 0

3 years ago

In a right triangle STR, angle T and R are complementary angles. The value of cos(T) is 9/41. What is the value of sin(R)?

alex41 [277]

Answer: C) 9/41

Step-by-step explanation: From the description, angle S is the right angle. Which means that angles T and R are complementary (they sum to 90 degrees). Because they are complementary, this means the cosine of one angle is equal to the sine of the other angle. If cos(T) is 9/41, then so is sin(R).

cr. USA Test Prep

5 0

3 years ago

there are 104 red candies in a candy machine. this represents 26% of the candy in the machine. how many total are in the candy m

Alborosie

There are 400 candies in the machine.

Step-by-step explanation:

Given,

Number of red candies in machine = 104

This represents 26% of the total candies.

Let,

x be the total candies in the machine.

According to statement;

26% of x = 104

$\frac{26}{100}*x=104\\0.26x=104$

Dividing both sides by 0.26

$\frac{0.26x}{0.26}=\frac{104}{0.26}\\x=400$

There are 400 candies in the machine.

Keywords: percentage, division

Learn more about percentages at:

#LearnwithBrainly

6 0

3 years ago

Test the series for convergence or divergence (using ratio test)

Triss [41]

Answer:

$\lim_{n \to \infty} U_n =0$

Given series is convergence by using Leibnitz's rule

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given series is an alternating series

∑ $(-1)^{n} \frac{n^{2} }{n^{3}+3 }$

Let $U_{n} = (-1)^{n} \frac{n^{2} }{n^{3}+3 }$

By using Leibnitz's rule

$U_{n} - U_{n-1} = \frac{n^{2} }{n^{3} +3} - \frac{(n-1)^{2} }{(n-1)^{3}+3 }$

$U_{n} - U_{n-1} = \frac{n^{2}(n-1)^{3} +3)-(n-1)^{2} (n^{3} +3) }{(n^{3} +3)(n-1)^{3} +3)}$

Uₙ-Uₙ₋₁ <0

<u><em>Step(ii):-</em></u>

$\lim_{n \to \infty} U_n = \lim_{n \to \infty}\frac{n^{2} }{n^{3}+3 }$

$= \lim_{n \to \infty}\frac{n^{2} }{n^{3}(1+\frac{3}{n^{3} } ) }$

= $= \lim_{n \to \infty}\frac{1 }{n(1+\frac{3}{n^{3} } ) }$

$=\frac{1}{infinite }$

=0

$\lim_{n \to \infty} U_n =0$

∴ Given series is converges

3 0

2 years ago

Find (gof)(3)<br> f(x) = |x+2|<br> g(x) = -x^2<br><br> A. -25<br> B. 1 <br> C. 4<br> D. -15

Ksenya-84 [330]

Answer:

A

Step-by-step explanation:

to find (g ￮ f)(3) , evaluate f(3) and substitute the value obtained into g(x)

f(3) = | 3 + 2 | = 5 , then

g(5) = - 5² = - 25

3 0

2 years ago

Read 2 more answers