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siniylev [52]
2 years ago
5

PLEASE HELP ME

Mathematics
1 answer:
ss7ja [257]2 years ago
8 0

Answer:

I believe this should be your answer Y=-7x+7

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An economist wants to estimate the mean per capita income (in thousands of dollars) for a major city in California. Suppose that
sergiy2304 [10]

Answer:

(22.0297, 23.3703)

Step-by-step explanation:

Given that an economist wants to estimate the mean per capita income (in thousands of dollars) for a major city in California.

Let X be per capita income (in thousands of dollars) for a major city in California.

Mean = 22.7

n = 183

Population std dev = 6.3

Since population std dev is known we can use Z critical value.

Std error = \frac{6.3}{\sqrt{183} } \\=0.4657

Z critical =1.44

Marginof error = ±1.44*0.4657=0.6706

Confidence interval 85%

=(22.7-0.6703, 22.7+0.6703)\\= (22.0297, 23.3703)

7 0
2 years ago
PLEASEEEEEE HELPPPPP!!
DaniilM [7]

Answer:

y-b+am/m

Step-by-step explanation:

y-b=m(x-a)

y-b=MX-ma

mx=y-b+ma

x=y-b+ma/m

4 0
2 years ago
5x - 2 = 8 + 5y<br> Solve for y and show work.
solniwko [45]
The answer is “x=y+2” hopefully this helps :)))))

7 0
3 years ago
I need yalls help. I'll brainlist u n give 5 star let's see who'll get it right.​
Vikki [24]

Answer:

A) is 29.76 B) IS $54

Step-by-step explanation:

you have to times 24 x 24% = 5.76 then you add 24 + 5.76 =29.76

7 0
3 years ago
PLEASE HELP I WILL MARK YOU AS BRAINLEST
denpristay [2]

Answer:

(i) Five number summary: Minimum value = 1, Q_1=18,Median=18.5, Q_3=20.5, Maximum value = 26.

(ii) IQR = 2.5, upper fence = 24.25 and lower fence = 14.25.

(iii) 26 is an outlier of the data.

Step-by-step explanation:

The given data set is

19, 18, 23, 18, 18, 26, 19, 16, 20, 18, 17, 21

Arrange the data set in ascending order.

16, 17, 18, 18, 18, 18, 19, 19, 20, 21, 23, 26

Divide the data set in 4 equal parts.

(16, 17, 18), (18, 18, 18), (19, 19, 20), (21, 23, 26)

Minimum value = 16

Q_1=\frac{18+18}{2}=18

Median=Q_2=\frac{18+19}{2}=18.5

Q_3=\frac{20+21}{2}=20.5

Maximum value = 26

The inter quartile range (IQR) of the data is

IQR=Q_3-Q_1=20.5-18=2.5

Upper fence :

Q_3+1.5(IQR)=20.5+1.5(2.5)=24.25

Lower fence :

Q_1-1.5(IQR)=18-1.5(2.5)=14.25

If the any element of the data set lies out side the upper fence and lower fence, then it is called an outlier.

26 ∉ [14.25, 24.25]

Therefore, 26 is an outlier of the data.

4 0
3 years ago
Read 2 more answers
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