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Stells [14]
2 years ago
15

8r-11r -14+5k-3 8c-5-9c -5y-7+6+13y 6k-7-19+k 2a-1-7b+4a-b+13

Mathematics
1 answer:
Ganezh [65]2 years ago
3 0

3r

-17 +5k

-1c - 5

8y -1

7k -26

4a -6b 12

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Nostrana [21]

Answer:

Over the interval [2, 4], the local minimum is –8.

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Step-by-step explanation:

The true statements are:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.  

Lets discuss each option one by one:

Over the interval [1, 3], the local minimum is 0

This is a false statement. Look at the graph. The minimum point given is (3.4,-8). Therefore the local minimum is -8 not 0

Over the interval [2, 4], the local minimum is –8.

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Over the interval [3, 5], the local minimum is –8.

According to the given minimum point, the local minimum  is -8 which is true

Over the interval [1, 4], the local maximum is 0.

Look at the graph. The maximum point given is (2,0). Thus this statement is true because local maximum is 0.

Over the interval [3, 5], the local maximum is 0.

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Hope you find this helpful. I am happy to help you whenever I can.

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