Answer:
myvals[1][2] = 4
Step-by-step explanation:
Int[][] myvals = {{2, 4, 6, 8}, {20, 40, 60, 80} }
This command means that we have the following matrix:
![\left[\begin{array}{cccc}2&4&6&8\\20&40&60&80\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D2%264%266%268%5C%5C20%2640%2660%2680%5Cend%7Barray%7D%5Cright%5D)
using the above two-dimensional array, what is the value of myvals[1][2]?
This is the element at first row, column 2.
First row is {2, 4, 6, 8}
First row, column 2 is 4. So
myvals[1][2] = 4
Answer:
No
Step-by-step explanation:
Given
f(x) = 
+ 11 ← substitute x = 1
f(1) = 
+ 11
= 
+ 11
is not real and therefore x = 1 does not have a real output for f(x)
Answer:
62 degrees
Step-by-step explanation:
the inside angles of a triangle always equal 180 degrees when added, so i just subtracted 56 and 62 from 180, also, the triangle is isosceles, which has 2 angles of equal value, so the unknown angle had to be equal to 62
Answer:
Step-by-step explanation:
Common denominator: 18
-14/18 + 11/18
= -3/18
Reduce:
-1/6
Hello! There are a few things that determine whether or not something is a function. In this case, to determine whether a relation is a function, we look at the domains, which are the x-coordinates, the first number of the pair. If the number occurs in the x-coordinate for more than one pair in a relation, then it's not a function. If a number only occurs as an x-coordinate once in the relation, then it's a function. In other words, they each have only one y-coordinate in the relation. For this question, the first, second, and third relations are functions. The fourth one is not a function, because the 3 has more than one y-coordinate, so it occurs as an x-coordinate more than once. Here are the answers easier to read.
1st : yes
2nd: yes
3rd: yes
4th: no
