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3 years ago

How do u find this area??

Mathematics

2 answers:

Helen [10]3 years ago

5 0

(12*22)/2 base times height divide by two

alexandr1967 [171]3 years ago

3 0

Answer:

you multiply

Step-by-step explanation:

multiple all the sides

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74ft <br> 24ft <br> b<br> What is the length of the missing leg?

amm1812

Answer: 70

Step-by-step explanation:

a^2 + b^2 = c^2

24^2 + b^2 = 74^2

576 + b^2 = 5,476

-576 -576

b^2 =4,900

(square root)

b =70

4 0

3 years ago

20 people applied for a job. Everyone either has a school certificate or diploma or even both. If 14 have school certificates an

STatiana [176]

Given:

Either has a school certificate or diploma or even both = 20 people

Having school certificates = 14

Having diplomas = 11

To find:

The number of people who have a school certificate only.

Solution:

Let A be the set of people who have school certificates and B be the set of people who have diplomas.

According to the given information, we have

$n(A)=14$

$n(B)=11$

$n(A\cup B)=20$

We know that,

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

$20=14+11-n(A\cap B)$

$20=25-n(A\cap B)$

Subtract both sides by 25.

$20-25=-n(A\cap B)$

$-5=-n(A\cap B)$

$5=n(A\cap B)$

We need to find the number of people who have a school certificate only, i.e. $n(A\cap B')$ .

$n(A\cap B')=n(A)-n(A\cap B)$

$n(A\cap B')=14-5$

$n(A\cap B')=9$

Therefore, 9 people have a school certificate only.

3 0

3 years ago

Solve the following matrix equations: (matrices)

Masja [62]

Step-by-step explanation:

$3X + \begin{pmatrix} 2 & 3 \\ 4 & 5 \end{pmatrix} = \begin{pmatrix} - 1 & 6 \\ 10 & 14 \end{pmatrix} \\ \\ 3X = \begin{pmatrix} - 1 & 6 \\ 10 & 14 \end{pmatrix} - \begin{pmatrix} 2 & 3 \\ 4 & 5 \end{pmatrix} \\ \\ 3X = \begin{pmatrix} - 1 - 2 & 6 - 3 \\ 10 - 4 & 14 - 5 \end{pmatrix}\\ \\ 3X = \begin{pmatrix} - 3 & 3 \\ 6 & 9\end{pmatrix}\\ \\ X = \frac{1}{3} \begin{pmatrix} - 3 & 3 \\ 6 & 9\end{pmatrix}\\ \\ X = \begin{pmatrix} \frac{ - 3}{3} & \frac{3}{3} \\ \\ \frac{6}{3} & \frac{9}{3} \end{pmatrix}\\ \\ \huge \red{ X} = \purple{ \begin{pmatrix} - 1 &1 \\ 2 & 3 \end{pmatrix}}$

$3X + 2I_3=\begin{pmatrix} 5 & 0 & -3 \\6 & 5 & 0\\ 9 & 6 & 5\end{pmatrix} \\\\3X + 2\begin{pmatrix} 1 & 0 & 0\\ 0 & 1 & 0\\ 0 & 0 & 1\end{pmatrix} =\begin{pmatrix} 5 & 0 & - 3\\6 & 5 & 0\\ 9 & 6 & 5 \end{pmatrix} \\\\3X + \begin{pmatrix} 2 & 0 & 0\\ 0 & 2 & 0\\ 0 & 0 & 2\end{pmatrix} =\begin{pmatrix} 5 & 0 & - 3\\ 6 & 5 & 0 \\ 9 & 6 & 5 \end{pmatrix} \\\\3X =\begin{pmatrix} 5 & 0 & -3 \\ 6 & 5 & 0 \\ 9 & 6 & 5 \end{pmatrix} - \begin{pmatrix} 2 & 0 & 0 \\ 0 & 2 & 0 \\ 0 & 0 & 2 \end{pmatrix} \\\\3X =\begin{pmatrix} 5-2 & 0-0 & -3-0 \\ 6-0 & 5-2 & 0-0 \\ 9-0 & 6-0 & 5-2 \end{pmatrix} \\\\3X =\begin{pmatrix} 3 & 0 & - 3 \\ 6 & 3 & 0 \\ 9 & 6 & 3 \end{pmatrix} \\\\X =\frac{1}{3} \begin{pmatrix} 3 & 0 & - 3 \\ 6 & 3 & 0 \\ 9 & 6 & 3 \end{pmatrix} \\\\X =\begin{pmatrix} \frac{3}{3} & \frac{0}{3} & \frac{-3}{3} \\\\ \frac{6}{3} & \frac{3}{3} & \frac{0}{3} \\\\ \frac{9}{3} & \frac{6}{3} & \frac{3}{3} \end{pmatrix} \\\\\huge\purple {X} =\orange{\begin{pmatrix} 1 & 0 & - 1\\ 2 & 1 & 0 \\ 3 & 2 & 1 \end{pmatrix}}\\$

8 0

3 years ago

The function f(x) = 1.50x + 12.50 relates how much Kelsey pays for digital service, f(x), to the number of movies, x, she stream

Kobotan [32]

Hi there! f(18) makes the value of x 18 and x is the number of movies watched in 1 month. Therefore, A and C are eliminated because we’re talking 18 movies, not 18 months. B is also out, because Kelsey would pay more than $27 a month for the service, especially with the service fee. 18 * 1.50 is 27 and 27 + 12.50 is 39.50. Kelsey spends $39.50 a month watching 18 movies per month. The answer is D.

4 0

3 years ago

Solve the equation 6.8x + 9.3 = -9.4 + 3.4 (2-5x)

neonofarm [45]

Answer:

Step-by-step explanation:

$6.8x + 9.3 = -9.4 + 3.4 (2-5x)\qquad\text{multiply both sides by 10}\\\\68x+93=-94+34(2-5x)\qquad\text{use distributive property}\\\\68x+93=-94+(34)(2)+(34)(-5x)\\\\68x+93=-94+68-170x\\\\68x+93=-26-170x\qquad\text{subtract 93 from both sides}\\\\68x=-119-170x\qquad\text{add 170x to both sides}\\\\238x=-119\qquad\text{divide both sides by 238}\\\\x=-\dfrac{119}{238}\\\\\boxed{x=-\dfrac{1}{2}}$

3 0

3 years ago

Read 2 more answers