0.6 cup of gliter is used for 1 cup of glue and 1.6 cup of gliter glue is made with 1 cup of glue.
Part A
Given that,
15 cup of gliter is for 25 cup of glue ,
Therefore, "X" cup of gliter is for 1 cup of glue
X = (1*15)/25
X= 0.6 cup of gliter
Part B,
Given that,
From part A 0.6 cup of gliter is for 1 cup of glue
Thus, 1 cup of glue and 0.6 cup of gliter when mixed will form "Y" cup of gliter glue
Now, Y= 0.6 cup of gliter + 1 cup of glue
Y= 1.6 cup of gliter glue
which approximates to 2 cup of gliter glue.
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5x-1 is greater than or equal to -11
Answer : -4a+10
Substitute (a-3) for x
-4(a-3)-2
-4a+12-2
-4a+10 but can also be written as -2(2a-5)
Sometimes system outputs are limited because the amount of the necessary information that is perceived in the system .
Answer:
(1) .20 (2) .40 (3) .12 (4) Less than
Step-by-step explanation:
You have to look at the table. There are 5 columns with 10 rows. 5x10=50
Then simply count the boxes that have the correct number of currency for instance, if they are asking for EXACTLY 1 dime then you rule out the ones that have 2 or 3 dimes and only the count the ones that have a single dime. So you count PDN but you would not count PDD. There are 20 boxes that have a single dime in them. 20 out of the 50 boxes. 20/50=.40 (answer 2)
The estimated probability that exactly two of the three coins Avery randomly picked are nickels is .
20
The estimated probability that exactly one of the three coins Avery randomly picked is a dime is .
40
The estimated probability that all three coins Avery randomly picked are pennies is .
12
The answer to #1 is .20 or 20% and the answer to #2 is .40 or 40%. 20% is less than 40% so...
The estimated probability that exactly two of the three coins Avery randomly picked are nickels is LESS THAN the estimated probability that exactly one of the three coins Avery randomly picked is a dime.
